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gohangoku58
 2 years ago
Best ResponseYou've already chosen the best response.0i mean is it cube root of unity ? or imaginary number i or something else ? if not, then u just said its variable, so x^4+x^2 can't equal 1.

gohangoku58
 2 years ago
Best ResponseYou've already chosen the best response.0or do u need to solve for x ???

koli123able
 2 years ago
Best ResponseYou've already chosen the best response.0I don't know that is what I am trying to figure out... this was the question in my paper and I left it blank

koli123able
 2 years ago
Best ResponseYou've already chosen the best response.0by means of anything

gohangoku58
 2 years ago
Best ResponseYou've already chosen the best response.0good luck with that :)

gohangoku58
 2 years ago
Best ResponseYou've already chosen the best response.0i think question is incomplete...we can solve for x, but can't prove that =1...

gohangoku58
 2 years ago
Best ResponseYou've already chosen the best response.0nopes, x not =1 :P

zostale
 2 years ago
Best ResponseYou've already chosen the best response.0x^4 +x^2=1 => => x^4 +x^2 1 = 0 => (x +0.786)*(x 0.786)*(x^2 +1.618) = 0 Real solutions: Root 1: 0.786 Root 2: 0.786 Complex roots: Root 3: 0+1.272 * i Root 4: 01.272 * i

gohangoku58
 2 years ago
Best ResponseYou've already chosen the best response.0are u solving that for x ,saura ?

zostale
 2 years ago
Best ResponseYou've already chosen the best response.0yeah should i give the source ? :P

gohangoku58
 2 years ago
Best ResponseYou've already chosen the best response.0take a screenshot of your question

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1353238271333:dwLooks like no solution

gohangoku58
 2 years ago
Best ResponseYou've already chosen the best response.0koli, any luck with screenshot ?

gohangoku58
 2 years ago
Best ResponseYou've already chosen the best response.0thats a good substitution to solve for x

gohangoku58
 2 years ago
Best ResponseYou've already chosen the best response.0u get quadratic in y

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.0x^4+x^21=0dw:1353238509864:dw

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1353238651184:dw

gohangoku58
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1353238684199:dw

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1353238793125:dw So, only two real roots

gohangoku58
 2 years ago
Best ResponseYou've already chosen the best response.0so for any of the 4 values of x we found above, u can prove that x^4+x^2= 1

koli123able
 2 years ago
Best ResponseYou've already chosen the best response.0how it is equal to 1??

gohangoku58
 2 years ago
Best ResponseYou've already chosen the best response.0solving for x in x^4+x^2=1 means ginding vales of x for which x^4+x^2 equals 1 so, for the 4 values we found, x^4+x^2 will equal 1.
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