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gohangoku58Best ResponseYou've already chosen the best response.0
i mean is it cube root of unity ? or imaginary number i or something else ? if not, then u just said its variable, so x^4+x^2 can't equal 1.
 one year ago

gohangoku58Best ResponseYou've already chosen the best response.0
or do u need to solve for x ???
 one year ago

koli123ableBest ResponseYou've already chosen the best response.0
I don't know that is what I am trying to figure out... this was the question in my paper and I left it blank
 one year ago

koli123ableBest ResponseYou've already chosen the best response.0
just prove it to 1
 one year ago

koli123ableBest ResponseYou've already chosen the best response.0
by means of anything
 one year ago

gohangoku58Best ResponseYou've already chosen the best response.0
good luck with that :)
 one year ago

gohangoku58Best ResponseYou've already chosen the best response.0
i think question is incomplete...we can solve for x, but can't prove that =1...
 one year ago

gohangoku58Best ResponseYou've already chosen the best response.0
nopes, x not =1 :P
 one year ago

gohangoku58Best ResponseYou've already chosen the best response.0
nopes, x not =1 :P
 one year ago

zostaleBest ResponseYou've already chosen the best response.0
x^4 +x^2=1 => => x^4 +x^2 1 = 0 => (x +0.786)*(x 0.786)*(x^2 +1.618) = 0 Real solutions: Root 1: 0.786 Root 2: 0.786 Complex roots: Root 3: 0+1.272 * i Root 4: 01.272 * i
 one year ago

gohangoku58Best ResponseYou've already chosen the best response.0
are u solving that for x ,saura ?
 one year ago

zostaleBest ResponseYou've already chosen the best response.0
yeah should i give the source ? :P
 one year ago

gohangoku58Best ResponseYou've already chosen the best response.0
take a screenshot of your question
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.0
dw:1353238271333:dwLooks like no solution
 one year ago

gohangoku58Best ResponseYou've already chosen the best response.0
koli, any luck with screenshot ?
 one year ago

gohangoku58Best ResponseYou've already chosen the best response.0
thats a good substitution to solve for x
 one year ago

gohangoku58Best ResponseYou've already chosen the best response.0
u get quadratic in y
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.0
x^4+x^21=0dw:1353238509864:dw
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.0
dw:1353238651184:dw
 one year ago

gohangoku58Best ResponseYou've already chosen the best response.0
dw:1353238684199:dw
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.0
dw:1353238793125:dw So, only two real roots
 one year ago

gohangoku58Best ResponseYou've already chosen the best response.0
so for any of the 4 values of x we found above, u can prove that x^4+x^2= 1
 one year ago

koli123ableBest ResponseYou've already chosen the best response.0
how it is equal to 1??
 one year ago

gohangoku58Best ResponseYou've already chosen the best response.0
solving for x in x^4+x^2=1 means ginding vales of x for which x^4+x^2 equals 1 so, for the 4 values we found, x^4+x^2 will equal 1.
 one year ago
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