anonymous
  • anonymous
If a given day is wet, the probability that the following day will also be wet is 0.8. If a given day is dry the probability that the following day will be dry is 0.6. Given that wednesday of a partciular week is dry work out the following; a)thursday and friday of the same week are wet days b)friday of the same week is a wet day c) In one season there were 44 cricket matches, each played over three consecutive days, in which the first and third days were dry. For how many of these matches would you expect the second day was wet?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
P(thursday and friday of the same week are wet days/Wednesday is dry) =(1-0.6)*0.8
anonymous
  • anonymous
P(friday of the same week is a wet day/Wednesday is dry) =0.6 * (1-0.6) + (1-0.6)*0.8
anonymous
  • anonymous
how did u solve for a?

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anonymous
  • anonymous
It is a conditional probability. And the given condition is that Wedenesday is wet.
anonymous
  • anonymous
So, the probability that Thursday will be wet is (1-0.6) And if Thursday will be wet the probability Friday will also be wet is 0.8. S0, for (a) it is (1-06)*0.8
anonymous
  • anonymous
which formula did you use like P(A/B)=P(A intersection B)/P(B) isnt this the formula for conditional probability?
anonymous
  • anonymous
Yes but not in this case.
anonymous
  • anonymous
Because we are given: P(next day is dry/today is dry)=0.6 P(next day is wet/today is wet)=0.8
anonymous
  • anonymous
got it?
anonymous
  • anonymous
yes !!Thanks !! n wat abt part c?
anonymous
  • anonymous
Isnt it (1-0.6)*(1-0.8)*44
anonymous
  • anonymous
answer is 8
anonymous
  • anonymous
It is ( Dry,Wet, Dry)/{(Dry,Dry,Dry) + (Dry, Wet , Dry))} *44 1*(1-0.6) * (1-0.8)/{(1*0.6*0.6) + (1* (1-0.6) * (1-0.8) }*44 =8
anonymous
  • anonymous
ok thanks
anonymous
  • anonymous
welcome

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