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possible zeros of
2x^5+3x^3+5x^26



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Skaematik
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possible zeros come from factors of 6
therefore: 1, 1, 2, 2, 3, 3
But mostly, you try 1 and 1 first

magepker728
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how did you get that?

magepker728
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isnt it factor of 6 and 2?

Skaematik
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That is a fact. Possible zeroes come from factors of the coefficient independent of x

Skaematik
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Use the remainder theory to find the zeroes for the polynomial

Skaematik
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if P(x) = 0, x is a zero.

magepker728
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well think you can find it or me for now?

Skaematik
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Find it yourself I just told you how to find it

magepker728
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lol im on a test bro..

Yahoo!
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2x^5+3x^3+5x^26 = 0
No of possible for Real Positive roots is 1
no of possible for Real ve roots is 2 or 0

cinar
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since f(0)<0 and f(1)>0 one root is between 0 and 1

cinar
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Bolzano theorem

magepker728
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i have to use the rational zeros theorem

cinar
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root is 0.83271 it is not integer, so it is not easy