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magepker728

  • 2 years ago

possible zeros of 2x^5+3x^3+5x^2-6

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  1. Skaematik
    • 2 years ago
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    possible zeros come from factors of 6 therefore: 1, -1, 2, -2, 3, -3 But mostly, you try 1 and -1 first

  2. magepker728
    • 2 years ago
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    how did you get that?

  3. magepker728
    • 2 years ago
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    isnt it factor of 6 and 2?

  4. Skaematik
    • 2 years ago
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    That is a fact. Possible zeroes come from factors of the coefficient independent of x

  5. Skaematik
    • 2 years ago
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    Use the remainder theory to find the zeroes for the polynomial

  6. Skaematik
    • 2 years ago
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    if P(x) = 0, x is a zero.

  7. magepker728
    • 2 years ago
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    well think you can find it or me for now?

  8. Skaematik
    • 2 years ago
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    Find it yourself I just told you how to find it

  9. magepker728
    • 2 years ago
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    lol im on a test bro..

  10. Yahoo!
    • 2 years ago
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    2x^5+3x^3+5x^2-6 = 0 No of possible for Real Positive roots is 1 no of possible for Real -ve roots is 2 or 0

  11. cinar
    • 2 years ago
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    since f(0)<0 and f(1)>0 one root is between 0 and 1

  12. cinar
    • 2 years ago
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    Bolzano theorem

  13. magepker728
    • 2 years ago
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    i have to use the rational zeros theorem

  14. cinar
    • 2 years ago
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    root is 0.83271 it is not integer, so it is not easy

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