Here's the question you clicked on:
jamesp201
In a certain year, the amount A of garbage in pounds produced after t days by an average household is given by A=5.5t. Graph the equation for t>0. How many days did it take for the average household to produce 200 pounds of garbage?
I am coming up with 18 but how do you graph that?
Well if you using a graphing calculator or even if your not it doesn't matter A will be the y values and t will be you x values. So in a graphing calculator it would look like this y= 5.5(x) and you can even add for (x > 0) or just look for the values when x is greater than 0.
That confused me a little more.
Are you using a graphing calculator?
I'll try and draw a graph for you.
A = garbage in pounds and t = days Well we don't know the days that is what is the question is asking: How many days did it take for the average household to produce 200 pounds of garbage? So A = 200 200 = 5.5 * t Divide both sides by 5.5 200/5.5 = t * 5.5/5.5 36.364 (rounded to three decimal places) = t So it took about 36.364 days for the average household to produce 200 lbs of garbage.
I hope this is making sense to you.
Oh, I got that part but in my exercise, I have to plot the equation and it only goes to 10
Do you see why 18 days is wrong?
oh..yes. I meant 36. I found an example for 100lbs and wrote that answer instead. Yes, I meant 36
All you have to do is pick points for example 2 for x then plug it in for t and what ever you get for A that is you y value. Since I said 2: A = 5.5 * 2 so you get the point x = 2, y = 11 or (2,11)
And just pick a few points that are evenly spread out and it doesn't have to be exact just relatively spread out.
Yes and no, I understand your example above but my exercise only does value up to 10 for x and for y.