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Yahoo!

  • 2 years ago

A 25000 Kg airplane takes off from rest and reaches 5000m altitude and cruises at 900km/h in 8 minutes .Find Avg Power ?

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  1. Yahoo!
    • 2 years ago
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    My Work: Pavg = W/t W = Delta K.E W = 25000 * 250*250 / 2 t = 8 * 60

  2. Yahoo!
    • 2 years ago
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    i got Pavg = 1.6 MW but the answer shuld be 4.2 MW

  3. terenzreignz
    • 2 years ago
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    Hang on a bit...

  4. Vincent-Lyon.Fr
    • 2 years ago
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    You have forgotten the gain in gravitational potential energy.

  5. Yahoo!
    • 2 years ago
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    We have Consider P.E here ?

  6. Vincent-Lyon.Fr
    • 2 years ago
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    Of course! How could you raise the altitude of the plane without providing energy?!

  7. Yahoo!
    • 2 years ago
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    Yup...i got..it...thx..)

  8. Yahoo!
    • 2 years ago
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    but @Vincent-Lyon.Fr we knw change in K.E is Work Done..Why cant we Use it here..)

  9. haridas_mandal
    • 2 years ago
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    Is it then mgh+delta K.E /t ?

  10. Vincent-Lyon.Fr
    • 2 years ago
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    You can, but there are two works to take into account: - motive work by the engine (positive) - negative work by the weight so change in KE = Wengine - Mgh or W engine = change in KE + change in PE

  11. Yahoo!
    • 2 years ago
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    Ok...Thxx....

  12. Vincent-Lyon.Fr
    • 2 years ago
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    yw :)

  13. Vincent-Lyon.Fr
    • 2 years ago
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    I see you are now getting to the energy concept. Soon you will be able to solve problems of mechanics by this method.

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