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freewilly922Best ResponseYou've already chosen the best response.1
If this expression didn't have variables but just numbers replacing them, you would give each piece a common denom. and then add. Do the same thing with the variables and then add them.
 one year ago

andreadesirepenBest ResponseYou've already chosen the best response.0
would the denom be x(x1) ?
 one year ago

freewilly922Best ResponseYou've already chosen the best response.1
For example \[\frac{1}{x+5}+\frac{10}{x^2+5x}\rightarrow\frac{1}{x+5}+\frac{10}{x(x+5)}\] the common Denom. is x(x+5) so all we need to do is multiply the first term by (x/x) \[\frac{1}{x+5}+\frac{10}{x(x+5)}\rightarrow\frac{1}{x+5}\frac{x}{x}+\frac{10}{x(x+5)}\]\] \[\frac{x}{x(x+5)}+\frac{10}{x(x+5)}=\frac{5+10}{x(x+5)}=\frac{15}{x(x+5)}\]
 one year ago

freewilly922Best ResponseYou've already chosen the best response.1
be careful with the negative signs though:)
 one year ago

andreadesirepenBest ResponseYou've already chosen the best response.0
so would it x1 or x+1 ?
 one year ago

freewilly922Best ResponseYou've already chosen the best response.1
\[x^2+x\rightarrow x(x+1)\]
 one year ago

andreadesirepenBest ResponseYou've already chosen the best response.0
is the answer 1x/x(x+1) ?
 one year ago
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