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## anonymous 4 years ago What is this simplified?

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1. anonymous

2. anonymous

If this expression didn't have variables but just numbers replacing them, you would give each piece a common denom. and then add. Do the same thing with the variables and then add them.

3. anonymous

would the denom be x(x-1) ?

4. anonymous

For example $\frac{1}{x+5}+\frac{10}{x^2+5x}\rightarrow\frac{1}{x+5}+\frac{10}{x(x+5)}$ the common Denom. is x(x+5) so all we need to do is multiply the first term by (x/x) $\frac{1}{x+5}+\frac{10}{x(x+5)}\rightarrow\frac{1}{x+5}\frac{x}{x}+\frac{10}{x(x+5)}$\] $\frac{x}{x(x+5)}+\frac{10}{x(x+5)}=\frac{5+10}{x(x+5)}=\frac{15}{x(x+5)}$

5. anonymous

yes!

6. anonymous

be careful with the negative signs though:)

7. anonymous

so would it x-1 or x+1 ?

8. anonymous

$x^2+x\rightarrow x(x+1)$

9. anonymous

is the answer 1-x/x(x+1) ?

10. anonymous

yes!

11. anonymous

Thanks!!!!!

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