anonymous
  • anonymous
What is this simplified?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
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anonymous
  • anonymous
If this expression didn't have variables but just numbers replacing them, you would give each piece a common denom. and then add. Do the same thing with the variables and then add them.
anonymous
  • anonymous
would the denom be x(x-1) ?

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anonymous
  • anonymous
For example \[\frac{1}{x+5}+\frac{10}{x^2+5x}\rightarrow\frac{1}{x+5}+\frac{10}{x(x+5)}\] the common Denom. is x(x+5) so all we need to do is multiply the first term by (x/x) \[\frac{1}{x+5}+\frac{10}{x(x+5)}\rightarrow\frac{1}{x+5}\frac{x}{x}+\frac{10}{x(x+5)}\]\] \[\frac{x}{x(x+5)}+\frac{10}{x(x+5)}=\frac{5+10}{x(x+5)}=\frac{15}{x(x+5)}\]
anonymous
  • anonymous
yes!
anonymous
  • anonymous
be careful with the negative signs though:)
anonymous
  • anonymous
so would it x-1 or x+1 ?
anonymous
  • anonymous
\[x^2+x\rightarrow x(x+1)\]
anonymous
  • anonymous
is the answer 1-x/x(x+1) ?
anonymous
  • anonymous
yes!
anonymous
  • anonymous
Thanks!!!!!

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