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freewilly922
 2 years ago
Best ResponseYou've already chosen the best response.1If this expression didn't have variables but just numbers replacing them, you would give each piece a common denom. and then add. Do the same thing with the variables and then add them.

andreadesirepen
 2 years ago
Best ResponseYou've already chosen the best response.0would the denom be x(x1) ?

freewilly922
 2 years ago
Best ResponseYou've already chosen the best response.1For example \[\frac{1}{x+5}+\frac{10}{x^2+5x}\rightarrow\frac{1}{x+5}+\frac{10}{x(x+5)}\] the common Denom. is x(x+5) so all we need to do is multiply the first term by (x/x) \[\frac{1}{x+5}+\frac{10}{x(x+5)}\rightarrow\frac{1}{x+5}\frac{x}{x}+\frac{10}{x(x+5)}\]\] \[\frac{x}{x(x+5)}+\frac{10}{x(x+5)}=\frac{5+10}{x(x+5)}=\frac{15}{x(x+5)}\]

freewilly922
 2 years ago
Best ResponseYou've already chosen the best response.1be careful with the negative signs though:)

andreadesirepen
 2 years ago
Best ResponseYou've already chosen the best response.0so would it x1 or x+1 ?

freewilly922
 2 years ago
Best ResponseYou've already chosen the best response.1\[x^2+x\rightarrow x(x+1)\]

andreadesirepen
 2 years ago
Best ResponseYou've already chosen the best response.0is the answer 1x/x(x+1) ?
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