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andreadesirepen

  • 3 years ago

What is this simplified?

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  1. andreadesirepen
    • 3 years ago
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  2. freewilly922
    • 3 years ago
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    If this expression didn't have variables but just numbers replacing them, you would give each piece a common denom. and then add. Do the same thing with the variables and then add them.

  3. andreadesirepen
    • 3 years ago
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    would the denom be x(x-1) ?

  4. freewilly922
    • 3 years ago
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    For example \[\frac{1}{x+5}+\frac{10}{x^2+5x}\rightarrow\frac{1}{x+5}+\frac{10}{x(x+5)}\] the common Denom. is x(x+5) so all we need to do is multiply the first term by (x/x) \[\frac{1}{x+5}+\frac{10}{x(x+5)}\rightarrow\frac{1}{x+5}\frac{x}{x}+\frac{10}{x(x+5)}\]\] \[\frac{x}{x(x+5)}+\frac{10}{x(x+5)}=\frac{5+10}{x(x+5)}=\frac{15}{x(x+5)}\]

  5. freewilly922
    • 3 years ago
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    yes!

  6. freewilly922
    • 3 years ago
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    be careful with the negative signs though:)

  7. andreadesirepen
    • 3 years ago
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    so would it x-1 or x+1 ?

  8. freewilly922
    • 3 years ago
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    \[x^2+x\rightarrow x(x+1)\]

  9. andreadesirepen
    • 3 years ago
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    is the answer 1-x/x(x+1) ?

  10. freewilly922
    • 3 years ago
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    yes!

  11. andreadesirepen
    • 3 years ago
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    Thanks!!!!!

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