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anonymous
 4 years ago
use factoring to solve (x1)^29=0
anonymous
 4 years ago
use factoring to solve (x1)^29=0

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1353268350386:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0First at all you should develop the expression between parentesis.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is this using factoring? I need to use all methods

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0isn't this extracting the square root

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@viniterranova do u mean foil it?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If you quadratic trinomial for (x1)^2 you will find. x^2+2x+1=9, so x^2+2x8=0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and that's for the factoring method right???

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Pay attetion. Just plug the x´s values +3 and 3 in the (x1)^2=9. See if this is values are valid for the expression.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x^2+2x8= 0 ; (x4)(x+2)=0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well i just wanna be sure

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Just solve the expression (x4)(x+2)=0.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wait, im not there yet, so you move the 9 to the other side, and foil (x1)^2 and I got x^22x+1?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Just pass the 8 for the first term of the equation and subtract it. and you got x^2+2x8= 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes, it´s 2x. Sorry for my lack of attention. So, the expression is x^22x8=0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and are the answers I got correct?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@Skaematik can u check my work

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@viniterranova I saw ur work, I understand now
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