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SkaematikBest ResponseYou've already chosen the best response.0
dw:1353268350386:dw
 one year ago

viniterranovaBest ResponseYou've already chosen the best response.0
First at all you should develop the expression between parentesis.
 one year ago

evy15Best ResponseYou've already chosen the best response.0
is this using factoring? I need to use all methods
 one year ago

evy15Best ResponseYou've already chosen the best response.0
isn't this extracting the square root
 one year ago

evy15Best ResponseYou've already chosen the best response.0
@viniterranova do u mean foil it?
 one year ago

viniterranovaBest ResponseYou've already chosen the best response.0
If you quadratic trinomial for (x1)^2 you will find. x^2+2x+1=9, so x^2+2x8=0
 one year ago

evy15Best ResponseYou've already chosen the best response.0
and that's for the factoring method right???
 one year ago

viniterranovaBest ResponseYou've already chosen the best response.0
Pay attetion. Just plug the x´s values +3 and 3 in the (x1)^2=9. See if this is values are valid for the expression.
 one year ago

viniterranovaBest ResponseYou've already chosen the best response.0
x^2+2x8= 0 ; (x4)(x+2)=0
 one year ago

evy15Best ResponseYou've already chosen the best response.0
well i just wanna be sure
 one year ago

viniterranovaBest ResponseYou've already chosen the best response.0
Just solve the expression (x4)(x+2)=0.
 one year ago

evy15Best ResponseYou've already chosen the best response.0
wait, im not there yet, so you move the 9 to the other side, and foil (x1)^2 and I got x^22x+1?
 one year ago

viniterranovaBest ResponseYou've already chosen the best response.0
Just pass the 8 for the first term of the equation and subtract it. and you got x^2+2x8= 0
 one year ago

viniterranovaBest ResponseYou've already chosen the best response.0
Yes, it´s 2x. Sorry for my lack of attention. So, the expression is x^22x8=0
 one year ago

evy15Best ResponseYou've already chosen the best response.0
and are the answers I got correct?
 one year ago

evy15Best ResponseYou've already chosen the best response.0
@Skaematik can u check my work
 one year ago

evy15Best ResponseYou've already chosen the best response.0
@viniterranova I saw ur work, I understand now
 one year ago
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