anonymous
  • anonymous
Find the points of intersection of each pair of curves in the given interval. i) y=sin2x, y=sinx
Mathematics
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anonymous
  • anonymous
Find the points of intersection of each pair of curves in the given interval. i) y=sin2x, y=sinx
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
set the y's equal...: sin2x = sinx given 2sinxcosx = sinx use the double angle formula for sine 2sinxcosx - sinx = 0 move the sinx over to the left side sinx(2cosx - 1) = 0 factor can you do the rest from here?
anonymous
  • anonymous
and btw, what is the interval?
anonymous
  • anonymous
\[(0 \pm 2*\pi*n,0),(\pi \pm 2*\pi*n,0)\]

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anonymous
  • anonymous
I got 0,0 but theres more intervals that icant get
anonymous
  • anonymous
no... what interval do you want to look for solution(s)? as it is stated in the problem, "... in the given interval"
anonymous
  • anonymous
what is the given interval?
anonymous
  • anonymous
SOrry the given interval is 0
anonymous
  • anonymous
ok... the interval is [0, 2pi]
anonymous
  • anonymous
so from the last equation: sinx(2cosx - 1) = 0 you'll need to set each factor equal to zero... sinx = 0 solve this... and also 2cosx - 1 = 0 solve this....
anonymous
  • anonymous
in the first equation, what angle between 0 and 2pi will give you a sine of zero?

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