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sabika13
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Find the points of intersection of each pair of curves in the given interval.
i) y=sin2x, y=sinx
 2 years ago
 2 years ago
sabika13 Group Title
Find the points of intersection of each pair of curves in the given interval. i) y=sin2x, y=sinx
 2 years ago
 2 years ago

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dpaInc Group TitleBest ResponseYou've already chosen the best response.0
set the y's equal...: sin2x = sinx given 2sinxcosx = sinx use the double angle formula for sine 2sinxcosx  sinx = 0 move the sinx over to the left side sinx(2cosx  1) = 0 factor can you do the rest from here?
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.0
and btw, what is the interval?
 2 years ago

surdawi Group TitleBest ResponseYou've already chosen the best response.0
\[(0 \pm 2*\pi*n,0),(\pi \pm 2*\pi*n,0)\]
 2 years ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
I got 0,0 but theres more intervals that icant get
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.0
no... what interval do you want to look for solution(s)? as it is stated in the problem, "... in the given interval"
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.0
what is the given interval?
 2 years ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
SOrry the given interval is 0</= x </= 2pi
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.0
ok... the interval is [0, 2pi]
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.0
so from the last equation: sinx(2cosx  1) = 0 you'll need to set each factor equal to zero... sinx = 0 solve this... and also 2cosx  1 = 0 solve this....
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.0
in the first equation, what angle between 0 and 2pi will give you a sine of zero?
 2 years ago
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