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sabika13
 2 years ago
Find the points of intersection of each pair of curves in the given interval.
i) y=sin2x, y=sinx
sabika13
 2 years ago
Find the points of intersection of each pair of curves in the given interval. i) y=sin2x, y=sinx

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dpaInc
 2 years ago
Best ResponseYou've already chosen the best response.0set the y's equal...: sin2x = sinx given 2sinxcosx = sinx use the double angle formula for sine 2sinxcosx  sinx = 0 move the sinx over to the left side sinx(2cosx  1) = 0 factor can you do the rest from here?

dpaInc
 2 years ago
Best ResponseYou've already chosen the best response.0and btw, what is the interval?

surdawi
 2 years ago
Best ResponseYou've already chosen the best response.0\[(0 \pm 2*\pi*n,0),(\pi \pm 2*\pi*n,0)\]

sabika13
 2 years ago
Best ResponseYou've already chosen the best response.0I got 0,0 but theres more intervals that icant get

dpaInc
 2 years ago
Best ResponseYou've already chosen the best response.0no... what interval do you want to look for solution(s)? as it is stated in the problem, "... in the given interval"

dpaInc
 2 years ago
Best ResponseYou've already chosen the best response.0what is the given interval?

sabika13
 2 years ago
Best ResponseYou've already chosen the best response.0SOrry the given interval is 0</= x </= 2pi

dpaInc
 2 years ago
Best ResponseYou've already chosen the best response.0ok... the interval is [0, 2pi]

dpaInc
 2 years ago
Best ResponseYou've already chosen the best response.0so from the last equation: sinx(2cosx  1) = 0 you'll need to set each factor equal to zero... sinx = 0 solve this... and also 2cosx  1 = 0 solve this....

dpaInc
 2 years ago
Best ResponseYou've already chosen the best response.0in the first equation, what angle between 0 and 2pi will give you a sine of zero?
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