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Find the points of intersection of each pair of curves in the given interval.
i) y=sin2x, y=sinx
 one year ago
 one year ago
Find the points of intersection of each pair of curves in the given interval. i) y=sin2x, y=sinx
 one year ago
 one year ago

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dpaIncBest ResponseYou've already chosen the best response.0
set the y's equal...: sin2x = sinx given 2sinxcosx = sinx use the double angle formula for sine 2sinxcosx  sinx = 0 move the sinx over to the left side sinx(2cosx  1) = 0 factor can you do the rest from here?
 one year ago

dpaIncBest ResponseYou've already chosen the best response.0
and btw, what is the interval?
 one year ago

surdawiBest ResponseYou've already chosen the best response.0
\[(0 \pm 2*\pi*n,0),(\pi \pm 2*\pi*n,0)\]
 one year ago

sabika13Best ResponseYou've already chosen the best response.0
I got 0,0 but theres more intervals that icant get
 one year ago

dpaIncBest ResponseYou've already chosen the best response.0
no... what interval do you want to look for solution(s)? as it is stated in the problem, "... in the given interval"
 one year ago

dpaIncBest ResponseYou've already chosen the best response.0
what is the given interval?
 one year ago

sabika13Best ResponseYou've already chosen the best response.0
SOrry the given interval is 0</= x </= 2pi
 one year ago

dpaIncBest ResponseYou've already chosen the best response.0
ok... the interval is [0, 2pi]
 one year ago

dpaIncBest ResponseYou've already chosen the best response.0
so from the last equation: sinx(2cosx  1) = 0 you'll need to set each factor equal to zero... sinx = 0 solve this... and also 2cosx  1 = 0 solve this....
 one year ago

dpaIncBest ResponseYou've already chosen the best response.0
in the first equation, what angle between 0 and 2pi will give you a sine of zero?
 one year ago
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