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## sabika13 3 years ago Find the points of intersection of each pair of curves in the given interval. i) y=sin2x, y=sinx

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1. dpaInc

set the y's equal...: sin2x = sinx given 2sinxcosx = sinx use the double angle formula for sine 2sinxcosx - sinx = 0 move the sinx over to the left side sinx(2cosx - 1) = 0 factor can you do the rest from here?

2. dpaInc

and btw, what is the interval?

3. surdawi

$(0 \pm 2*\pi*n,0),(\pi \pm 2*\pi*n,0)$

4. sabika13

I got 0,0 but theres more intervals that icant get

5. dpaInc

no... what interval do you want to look for solution(s)? as it is stated in the problem, "... in the given interval"

6. dpaInc

what is the given interval?

7. sabika13

SOrry the given interval is 0</= x </= 2pi

8. dpaInc

ok... the interval is [0, 2pi]

9. dpaInc

so from the last equation: sinx(2cosx - 1) = 0 you'll need to set each factor equal to zero... sinx = 0 solve this... and also 2cosx - 1 = 0 solve this....

10. dpaInc

in the first equation, what angle between 0 and 2pi will give you a sine of zero?

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