Here's the question you clicked on:
sabika13
Find the points of intersection of each pair of curves in the given interval. i) y=sin2x, y=sinx
set the y's equal...: sin2x = sinx given 2sinxcosx = sinx use the double angle formula for sine 2sinxcosx - sinx = 0 move the sinx over to the left side sinx(2cosx - 1) = 0 factor can you do the rest from here?
and btw, what is the interval?
\[(0 \pm 2*\pi*n,0),(\pi \pm 2*\pi*n,0)\]
I got 0,0 but theres more intervals that icant get
no... what interval do you want to look for solution(s)? as it is stated in the problem, "... in the given interval"
what is the given interval?
SOrry the given interval is 0</= x </= 2pi
ok... the interval is [0, 2pi]
so from the last equation: sinx(2cosx - 1) = 0 you'll need to set each factor equal to zero... sinx = 0 solve this... and also 2cosx - 1 = 0 solve this....
in the first equation, what angle between 0 and 2pi will give you a sine of zero?