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burhan101 Group TitleBest ResponseYou've already chosen the best response.0
how do i make the left side into one big fraction
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
\[\huge \frac{ 1 }{ sinx+1 }  \frac{ 1 }{ sinx1 } = \frac{ 2 }{ 1\sin^2x}\]
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
typed it wrong wooops
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.2
get common denominators on the left side: \(\huge \frac{ 1 }{ sinx+1 }\cdot (\color {red}{\frac{ sinx1 }{ sinx1 }})  \frac{ 1 }{ sinx1 }\cdot( \color {red}{\frac{ sinx+1 }{ sinx+1 }}) = \frac{ 2 }{ 1\sin^2x} \)
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.2
so the left side in simplified form will be: \(\huge \frac{(sinx1)(sinx+1)}{sin^2x1} \) can you simplify this?
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
no that's where i get stuck how would i subtract the numerator
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.2
just use distributive property to get rid of the parenthesis...
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
@dpaInc i get this \[\huge \frac{ \sin^2x+sinxsinx1 }{ sinx^21 }\]
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.2
how did you get that? all you're doing is subtracting....: \(\huge \frac{(sinx1)(sinx+1)}{sin^2x1} \) =\(\huge \frac{1\cdot (sinx1)1\cdot (sinx+1)}{sin^2x1} \) =\(\huge \frac{sinx1sinx1}{sin^2x1} \) =\(\huge \frac{2}{sin^2x1} \) =\(\huge \frac{2}{1sin^2x} \)
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
sinx1sinx1 = 2 is that a trig rule or what ? :S
 2 years ago
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