Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

burhan101 Group Title

Trig identity.. I don't understand this one at all

  • 2 years ago
  • 2 years ago

  • This Question is Closed
  1. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    how do i make the left side into one big fraction

    • 2 years ago
  2. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\huge \frac{ 1 }{ sinx+1 } - \frac{ 1 }{ sinx-1 } = \frac{ 2 }{ 1-\sin^2x}\]

    • 2 years ago
  3. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    typed it wrong wooops

    • 2 years ago
  4. dpaInc Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    get common denominators on the left side: \(\huge \frac{ 1 }{ sinx+1 }\cdot (\color {red}{\frac{ sinx-1 }{ sinx-1 }}) - \frac{ 1 }{ sinx-1 }\cdot( \color {red}{\frac{ sinx+1 }{ sinx+1 }}) = \frac{ 2 }{ 1-\sin^2x} \)

    • 2 years ago
  5. dpaInc Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    so the left side in simplified form will be: \(\huge \frac{(sinx-1)-(sinx+1)}{sin^2x-1} \) can you simplify this?

    • 2 years ago
  6. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    no that's where i get stuck how would i subtract the numerator

    • 2 years ago
  7. dpaInc Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    just use distributive property to get rid of the parenthesis...

    • 2 years ago
  8. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    @dpaInc i get this \[\huge \frac{ \sin^2x+sinx-sinx-1 }{ sinx^2-1 }\]

    • 2 years ago
  9. dpaInc Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    how did you get that? all you're doing is subtracting....: \(\huge \frac{(sinx-1)-(sinx+1)}{sin^2x-1} \) =\(\huge \frac{1\cdot (sinx-1)-1\cdot (sinx+1)}{sin^2x-1} \) =\(\huge \frac{sinx-1-sinx-1}{sin^2x-1} \) =\(\huge \frac{-2}{sin^2x-1} \) =\(\huge \frac{2}{1-sin^2x} \)

    • 2 years ago
  10. burhan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    sinx-1-sinx-1 = -2 is that a trig rule or what ? :S

    • 2 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.