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burhan101Best ResponseYou've already chosen the best response.0
how do i make the left side into one big fraction
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
\[\huge \frac{ 1 }{ sinx+1 }  \frac{ 1 }{ sinx1 } = \frac{ 2 }{ 1\sin^2x}\]
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
typed it wrong wooops
 one year ago

dpaIncBest ResponseYou've already chosen the best response.2
get common denominators on the left side: \(\huge \frac{ 1 }{ sinx+1 }\cdot (\color {red}{\frac{ sinx1 }{ sinx1 }})  \frac{ 1 }{ sinx1 }\cdot( \color {red}{\frac{ sinx+1 }{ sinx+1 }}) = \frac{ 2 }{ 1\sin^2x} \)
 one year ago

dpaIncBest ResponseYou've already chosen the best response.2
so the left side in simplified form will be: \(\huge \frac{(sinx1)(sinx+1)}{sin^2x1} \) can you simplify this?
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
no that's where i get stuck how would i subtract the numerator
 one year ago

dpaIncBest ResponseYou've already chosen the best response.2
just use distributive property to get rid of the parenthesis...
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
@dpaInc i get this \[\huge \frac{ \sin^2x+sinxsinx1 }{ sinx^21 }\]
 one year ago

dpaIncBest ResponseYou've already chosen the best response.2
how did you get that? all you're doing is subtracting....: \(\huge \frac{(sinx1)(sinx+1)}{sin^2x1} \) =\(\huge \frac{1\cdot (sinx1)1\cdot (sinx+1)}{sin^2x1} \) =\(\huge \frac{sinx1sinx1}{sin^2x1} \) =\(\huge \frac{2}{sin^2x1} \) =\(\huge \frac{2}{1sin^2x} \)
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
sinx1sinx1 = 2 is that a trig rule or what ? :S
 one year ago
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