Calculate the concentration of potassium ion in grams per liter after mixing 100ml of 0.250M KCl and 200ml of 0.1 M K2SO4

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Calculate the concentration of potassium ion in grams per liter after mixing 100ml of 0.250M KCl and 200ml of 0.1 M K2SO4

Chemistry
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

first you write dissociation of KCl and K2SO4 where you assume that KCl and K2SO4 are completely dissasociated, then you set the ratio for each K+ ion and its compound and from there get the amount of K+ ions from each compound, sum them up and calculate mass, after that divide with summed volume and there you go.
What exactly do I sum up?
KCl -> K+ + Cl- K2SO4 -> 2K+ + SO4 2- c= n/V -> n= c*V n(KCl) = c(KCl) * V(KCl) n1(K+)/n(KCl) = 1/1 = 1 n1(K+) = n(KCl) n(K2SO4) = c(K2SO4) * V(K2SO4) n2(K+)/n(K2SO4) = 2/1 = 2 n2(K+) = 2*n(K2SO4) n(K+) = n1(K+) + n2(K+) n= m/M -> m = n*M m(K+) = n(K+) * M(K) V = V(KCl) + V(K2SO4) gama - mass concentration gama = m(K+) / V

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

thank you!

Not the answer you are looking for?

Search for more explanations.

Ask your own question