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freewilly922 Group TitleBest ResponseYou've already chosen the best response.0
Do you know how to do synthetic division?
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
1 and 1 do not work (check those first) next possibility is \(\frac{1}{2}\) check that next
 one year ago

freewilly922 Group TitleBest ResponseYou've already chosen the best response.0
Where does the 1/2 guess come from? just standard practice for +1 endings?
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
the constant is 1 the leading coefficient is 4 possible rational zeros are fractions where the numerator divides 1 and the denominator divides 4
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
possible rational zeros are \[\pm 1,\pm\frac{1}{2},\pm\frac{1}{4}\]
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
1 and 1 are easiest to check because you can pretty much do it in your head after you see they don't work, i would try \(\frac{1}{2}\) and lo and behold it does work
 one year ago

Cj1213 Group TitleBest ResponseYou've already chosen the best response.0
are you dividing to get this like synthetic division.
 one year ago

Cj1213 Group TitleBest ResponseYou've already chosen the best response.0
I need help with the steps getting started
 one year ago

freewilly922 Group TitleBest ResponseYou've already chosen the best response.0
dw:1353292321982:dw The biggest problem is that synth. Division is hard to show how to do on open study. This is an example if you were to check if (x1) divides 4x^3  6x^2 +1 with 4 6 0 1 as the coefficients. You basically have 1 4 6 0 1 where the first 1 is a from (xa) or (x1) which is what we are checking. so you drop the first number down 4 multiply it by 1 to get 4. Add this 4 to 6 to get 2. Multiply this again by 1 to get 2 to add this to 0 to drop a 2. Multiply this again by 1 to get 2 to add to the last 1 to get 1. Since this is not a 0 then (x1) doesn't divide 4x^3  6x^2 +1. need to try again.
 one year ago

Cj1213 Group TitleBest ResponseYou've already chosen the best response.0
okay i'll figure it out it is a start.
 one year ago

freewilly922 Group TitleBest ResponseYou've already chosen the best response.0
Definitely write down what @satellite73 wrote down about how to choose what to check.
 one year ago

Cj1213 Group TitleBest ResponseYou've already chosen the best response.0
Its been awhile since ive worked with synthetic division. all the answers are not rational. but once I get 1/2 I can take the equation and do the quadratic formula to get the other answers
 one year ago
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