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An object is dropped from a tower of height 224 feet, subject to only the constant acceleration of −32 ft/sec2 due to gravity. (d) What should its initial velocity be in order to strike the ground after 1 second?

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clearly the word "dropped" here is inappropriate, since they are asking what hthe initial velocity should be if it is dropped, the initial velocity is 0!!
In order to reach the ground in 1 second the Vi would have to have a negative velocity of some value otherwise it would not be fast enough

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Other answers:

oh you put in the word "dropped" tsk tsk
I just can't find the corriect value
sorry that's what the question said
lets try this \[a(t)=-32, v(t)=-32t^2+v_0, p(t)=-16t^2+v_0t+224\]
or more commonly written \[h(t)=-16t^2+v_0t+224\]
set equal to zero, then put \(t=1\) to solve for \(v_0\)
oh no your answer will have a \(v_0\) in it
I plugged in 1 for t and got the 208
oh wait, you are right put \(t=1\) set equal to 0 solve for \(v_0\)
\[0=-16+v_0+224\] \[v_0=-208\]
i see the problem it is negative and you put 208 i bet
Oh! Darn. I even said it have to be negative in the beginning didn't I? X(
yes you did
I plugged it in :) it's right :P thanks! I knew I had to be right but I'm always missing some stupid detail!
yw always good to have another pair of eyes

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