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byerskm2 Group Title

An object is dropped from a tower of height 224 feet, subject to only the constant acceleration of −32 ft/sec2 due to gravity. (d) What should its initial velocity be in order to strike the ground after 1 second?

  • one year ago
  • one year ago

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  1. satellite73 Group Title
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    clearly the word "dropped" here is inappropriate, since they are asking what hthe initial velocity should be if it is dropped, the initial velocity is 0!!

    • one year ago
  2. byerskm2 Group Title
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    http://i50.tinypic.com/34ip8a8.png

    • one year ago
  3. byerskm2 Group Title
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    In order to reach the ground in 1 second the Vi would have to have a negative velocity of some value otherwise it would not be fast enough

    • one year ago
  4. satellite73 Group Title
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    oh you put in the word "dropped" tsk tsk

    • one year ago
  5. byerskm2 Group Title
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    I just can't find the corriect value

    • one year ago
  6. byerskm2 Group Title
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    sorry that's what the question said

    • one year ago
  7. byerskm2 Group Title
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    :P

    • one year ago
  8. satellite73 Group Title
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    lets try this \[a(t)=-32, v(t)=-32t^2+v_0, p(t)=-16t^2+v_0t+224\]

    • one year ago
  9. byerskm2 Group Title
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    yes

    • one year ago
  10. satellite73 Group Title
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    or more commonly written \[h(t)=-16t^2+v_0t+224\]

    • one year ago
  11. satellite73 Group Title
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    set equal to zero, then put \(t=1\) to solve for \(v_0\)

    • one year ago
  12. byerskm2 Group Title
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    208?

    • one year ago
  13. satellite73 Group Title
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    \[t^2-\frac{v_0}{16}-14=0\]

    • one year ago
  14. satellite73 Group Title
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    oh no your answer will have a \(v_0\) in it

    • one year ago
  15. byerskm2 Group Title
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    I plugged in 1 for t and got the 208

    • one year ago
  16. satellite73 Group Title
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    oh wait, you are right put \(t=1\) set equal to 0 solve for \(v_0\)

    • one year ago
  17. satellite73 Group Title
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    \[0=-16+v_0+224\] \[v_0=-208\]

    • one year ago
  18. satellite73 Group Title
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    i see the problem it is negative and you put 208 i bet

    • one year ago
  19. byerskm2 Group Title
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    Oh! Darn. I even said it have to be negative in the beginning didn't I? X(

    • one year ago
  20. satellite73 Group Title
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    yes you did

    • one year ago
  21. byerskm2 Group Title
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    I plugged it in :) it's right :P thanks! I knew I had to be right but I'm always missing some stupid detail!

    • one year ago
  22. satellite73 Group Title
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    yw always good to have another pair of eyes

    • one year ago
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