Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

UnkleRhaukusBest ResponseYou've already chosen the best response.0
\[\begin{align*} \mathcal L\big\{f(xa)h(xa)\big\}&=\int\limits_0^\infty f(xa)h(xa)e^{px}\text dx\\ \text{let } t=xa\\ \text dt=\text dx\\ x=0\rightarrow t=a\\ x=\infty\rightarrow t=\infty\\ &=\int\limits_{a}^\infty f(t)h(t)e^{p(t+a)}\text dt\\ &= \\ \end{align*}\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
\[\begin{align*} &=\int\limits_{a}^\infty f(t)h(t)e^{p(t+a)}\text dt\\ &=e^{pa}\int\limits_{0}^\infty f(t)e^{pt}\text dt\\ &=e^{pa}F(p)\ \\ \end{align*}\] is this right?
 one year ago

ChmEBest ResponseYou've already chosen the best response.0
Thats the same thing I show in my book. I just learned this last week. I don't get it either
 one year ago

ChmEBest ResponseYou've already chosen the best response.0
The h(xa) or in my book u(ta) as I understand it is just an on off switch for the discontinuous function
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
yeah , h, u , or \(\theta\) are used for the heaviside unit step function
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
\[\mathcal L\big\{f(xa)h(xa)\big\}=e^{pa}F(p)\] \[f(xa)h(xa)=\mathcal L^{1}\big\{e^{pa}F(p)\big\}\]
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.