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burhan101

  • 3 years ago

How do i simplify this

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  1. burhan101
    • 3 years ago
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    \[\huge \frac{ 1+\frac{ sinx }{ cosx } }{ 1- \frac{ sinx }{ cosx } } =\]

  2. UnkleRhaukus
    • 3 years ago
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    \[\frac{ \sin x }{ \cos x } =\tan x\]

  3. burhan101
    • 3 years ago
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    yea i am not allowed to use tan

  4. burhan101
    • 3 years ago
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    i have to keep it only sin & cos that's why i simplified it originally from tan

  5. UnkleRhaukus
    • 3 years ago
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    \[ \frac{ 1+\frac{ \sin x }{ \cos x } }{ 1- \frac{ \sin x }{ \cos x } } =\frac{ \cos x+ \sin x }{\cos x- \sin x }\]

  6. burhan101
    • 3 years ago
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    how did you do that ? :S

  7. UnkleRhaukus
    • 3 years ago
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    \[\frac{ 1+\frac{ \sin x }{ \cos x } }{ 1- \frac{ \sin x }{ \cos x } }\times1\] \[\frac{ 1+\frac{ \sin x }{ \cos x } }{ 1- \frac{ \sin x }{ \cos x } }\times\frac {\cos x}{\cos x}\] \[ =\frac{ \cos x+ \sin x }{\cos x- \sin x }\]\]

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