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MikiaseKebede Group TitleBest ResponseYou've already chosen the best response.0
solve what
 2 years ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ dy }{ dx } = e^{x+y} (x+y)^{1}  1 \]
 2 years ago

MikiaseKebede Group TitleBest ResponseYou've already chosen the best response.0
dame i am not at a level like this one, i am sorry
 2 years ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.0
ok..., no problem @MikiaseKebede nevermind :)
 2 years ago

MikiaseKebede Group TitleBest ResponseYou've already chosen the best response.0
you should ask http://openstudy.com/users/jim_thompson5910
 2 years ago

MikiaseKebede Group TitleBest ResponseYou've already chosen the best response.0
he is good
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.0
i think you have to apply the product rule
 2 years ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.0
what did u get it??
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.0
hmm i havent solved it just trying to help you with it
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.0
or there is another easier way u =x+y du/dx = 1 du =dx
 2 years ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
http://mathhelpforum.com/differentialequations/194955solvingdydxexy.html
 2 years ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
solve dy/dx = e^{x+y}
 2 years ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.0
@mayankdevnani No, i mean \[\frac{ dy }{ dx } = e^{x+y} (x+y)^{1}  1 \]
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.4
let \[z=x+y\]and u have\[\frac{\text{d}z}{\text{d}x}=1+\frac{\text{d}y}{\text{d}x}\]put this in the original equation\[\frac{\text{d}z}{\text{d}x}1=\frac{e^z}{z}1\]\[\frac{\text{d}z}{\text{d}x}=\frac{e^z}{z}\]u have a separable differential equation :)
 2 years ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.0
ok @mukushla, then i got \[\int\limits z dz = \int\limits e^{z} dx\] \[\frac{ z^{2} }{ 2 } = e^{z} x\] \[\frac{ (x+y)^{2} }{ 2 } = e^{x+y} x\] Did I miss something?
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.4
emm...there is a little mistake in ur separation\[ze^{z}\text{d}z=\text{d}x\]
 2 years ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.0
\[\int\limits \frac{ z }{ e^{z} } dz = \int\limits dx \]
 2 years ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ 1 + z }{ e^{z} } = x\] \[\frac{ 1 + x + y }{ e^{x+y} } = x\] \[\frac{ x+y1 }{ x } = e^{x+y}\]
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.4
integration by parts for z :)
 2 years ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.0
\[\int\limits ze^{z} dz = \int\limits dx\] u = z, \(dv = e^{z} dz\), then du = dz, and \(v = e^{z}\) So \[ze^{z}  \int\limits e^{z} dz = \int\limits dx\] \[ze^{z}  \frac{ e^{z} }{ \ln e } = x\] then ??
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
ln e = 1 re substitute z as x+y
 2 years ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.0
\[ze^{z}  e^{z} = x\] \[(x+y)e^{(x+y)}  e^{(x+y)} = x\] \[(xy  1) e^{(x+y)} = x\] \[(1+x+y) = x e^{(x+y)}\]
 2 years ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.0
did i miss something?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
nopes, thats correct. :)
 2 years ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.0
so how to find y?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
i don't think, y can be isolated....
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/input/?i=%281%2Bx%2By%29%3D%E2%88%92xe%5E%28x%2By%29+solve+for+y
 2 years ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.0
what it means to "W is the product log function"??
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
even idk that... not a standard function for sure....
 2 years ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.0
ok Thank you all so much! i really appreciate it :)
 2 years ago
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