Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

gerryliyana Group Title

solve dy/dx = e^{x+y} (x+y)^{-1} - 1 y ????

  • 2 years ago
  • 2 years ago

  • This Question is Closed
  1. MikiaseKebede Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    solve what

    • 2 years ago
  2. gerryliyana Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\frac{ dy }{ dx } = e^{x+y} (x+y)^{-1} - 1 \]

    • 2 years ago
  3. MikiaseKebede Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    dame i am not at a level like this one, i am sorry

    • 2 years ago
  4. gerryliyana Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ok..., no problem @MikiaseKebede nevermind :)

    • 2 years ago
  5. MikiaseKebede Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    you should ask http://openstudy.com/users/jim_thompson5910

    • 2 years ago
  6. MikiaseKebede Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    him

    • 2 years ago
  7. gerryliyana Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ok

    • 2 years ago
  8. MikiaseKebede Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    he is good

    • 2 years ago
  9. nubeer Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    i think you have to apply the product rule

    • 2 years ago
  10. gerryliyana Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    what did u get it??

    • 2 years ago
  11. nubeer Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    hmm i havent solved it just trying to help you with it

    • 2 years ago
  12. nubeer Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    or there is another easier way u =x+y du/dx = 1 du =dx

    • 2 years ago
  13. mayankdevnani Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    http://mathhelpforum.com/differential-equations/194955-solving-dy-dx-e-x-y.html

    • 2 years ago
  14. mayankdevnani Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    solve dy/dx = e^{x+y}

    • 2 years ago
  15. gerryliyana Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    @mayankdevnani No, i mean \[\frac{ dy }{ dx } = e^{x+y} (x+y)^{-1} - 1 \]

    • 2 years ago
  16. mukushla Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    let \[z=x+y\]and u have\[\frac{\text{d}z}{\text{d}x}=1+\frac{\text{d}y}{\text{d}x}\]put this in the original equation\[\frac{\text{d}z}{\text{d}x}-1=\frac{e^z}{z}-1\]\[\frac{\text{d}z}{\text{d}x}=\frac{e^z}{z}\]u have a separable differential equation :)

    • 2 years ago
  17. gerryliyana Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ok @mukushla, then i got \[\int\limits z dz = \int\limits e^{z} dx\] \[\frac{ z^{2} }{ 2 } = e^{z} x\] \[\frac{ (x+y)^{2} }{ 2 } = e^{x+y} x\] Did I miss something?

    • 2 years ago
  18. mukushla Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    emm...there is a little mistake in ur separation\[ze^{-z}\text{d}z=\text{d}x\]

    • 2 years ago
  19. gerryliyana Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\int\limits \frac{ z }{ e^{z} } dz = \int\limits dx \]

    • 2 years ago
  20. mukushla Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    exactly

    • 2 years ago
  21. gerryliyana Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\frac{ -1 + z }{ e^{z} } = x\] \[\frac{ -1 + x + y }{ e^{x+y} } = x\] \[\frac{ x+y-1 }{ x } = e^{x+y}\]

    • 2 years ago
  22. mukushla Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    integration by parts for z :)

    • 2 years ago
  23. gerryliyana Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\int\limits ze^{-z} dz = \int\limits dx\] u = z, \(dv = e^{-z} dz\), then du = dz, and \(v = -e^{-z}\) So \[-ze^{-z} - \int\limits -e^{-z} dz = \int\limits dx\] \[-ze^{-z} - \frac{ e^{-z} }{ \ln e } = x\] then ??

    • 2 years ago
  24. hartnn Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ln e = 1 re substitute z as x+y

    • 2 years ago
  25. gerryliyana Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    \[-ze^{-z} - e^{-z} = x\] \[-(x+y)e^{-(x+y)} - e^{(x+y)} = x\] \[(-x-y - 1) e^{-(x+y)} = x\] \[(1+x+y) =- x e^{(x+y)}\]

    • 2 years ago
  26. gerryliyana Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    did i miss something?

    • 2 years ago
  27. hartnn Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    nopes, thats correct. :)

    • 2 years ago
  28. gerryliyana Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    so how to find y?

    • 2 years ago
  29. hartnn Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    i don't think, y can be isolated....

    • 2 years ago
  30. hartnn Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    http://www.wolframalpha.com/input/?i=%281%2Bx%2By%29%3D%E2%88%92xe%5E%28x%2By%29+solve+for+y

    • 2 years ago
  31. gerryliyana Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    what it means to "W is the product log function"??

    • 2 years ago
  32. hartnn Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    even idk that... not a standard function for sure....

    • 2 years ago
  33. gerryliyana Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ok Thank you all so much! i really appreciate it :)

    • 2 years ago
  34. hartnn Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    welcome ^_^

    • 2 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.