anonymous
  • anonymous
trig identity
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
\[\large \frac{ 1+2sinxcosx }{ \cos^2x-\sin^2x }\]
anonymous
  • anonymous
Which part did you get stuck at
anonymous
  • anonymous
that equals \[\large\frac{ cosx+sinx }{ cosx-sinx }\]

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anonymous
  • anonymous
i can't seem to make them equal :(
anonymous
  • anonymous
1 + 2sinx cosx = sin²x + 2sinxcosx + cos²x = ( sinx + cosx)²
anonymous
  • anonymous
cos²x - sin²x = ( cosx - sinx ) ( cosx + sinx)
anonymous
  • anonymous
Now simplify upper and lower => the left side :)
anonymous
  • anonymous
|dw:1353299245697:dw| this right
anonymous
  • anonymous
Can you simplify them?
anonymous
  • anonymous
yup, got it cosx+sinx/cosx-sinx
anonymous
  • anonymous
LHS=RSH thankyou ! :D

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