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burhan101 Group Title

trig identity

  • one year ago
  • one year ago

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  1. burhan101 Group Title
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    \[\large \frac{ 1+2sinxcosx }{ \cos^2x-\sin^2x }\]

    • one year ago
  2. Skaematik Group Title
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    Which part did you get stuck at

    • one year ago
  3. burhan101 Group Title
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    that equals \[\large\frac{ cosx+sinx }{ cosx-sinx }\]

    • one year ago
  4. burhan101 Group Title
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    i can't seem to make them equal :(

    • one year ago
  5. Chlorophyll Group Title
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    1 + 2sinx cosx = sin²x + 2sinxcosx + cos²x = ( sinx + cosx)²

    • one year ago
  6. Chlorophyll Group Title
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    cos²x - sin²x = ( cosx - sinx ) ( cosx + sinx)

    • one year ago
  7. Chlorophyll Group Title
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    Now simplify upper and lower => the left side :)

    • one year ago
  8. burhan101 Group Title
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    |dw:1353299245697:dw| this right

    • one year ago
  9. Chlorophyll Group Title
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    Can you simplify them?

    • one year ago
  10. burhan101 Group Title
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    yup, got it cosx+sinx/cosx-sinx

    • one year ago
  11. burhan101 Group Title
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    LHS=RSH thankyou ! :D

    • one year ago
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