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burhan101Best ResponseYou've already chosen the best response.0
\[\large \frac{ 1+2sinxcosx }{ \cos^2x\sin^2x }\]
 one year ago

SkaematikBest ResponseYou've already chosen the best response.0
Which part did you get stuck at
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
that equals \[\large\frac{ cosx+sinx }{ cosxsinx }\]
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
i can't seem to make them equal :(
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.1
1 + 2sinx cosx = sin²x + 2sinxcosx + cos²x = ( sinx + cosx)²
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.1
cos²x  sin²x = ( cosx  sinx ) ( cosx + sinx)
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.1
Now simplify upper and lower => the left side :)
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
dw:1353299245697:dw this right
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.1
Can you simplify them?
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
yup, got it cosx+sinx/cosxsinx
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
LHS=RSH thankyou ! :D
 one year ago
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