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burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0\[\large \frac{ 1+2sinxcosx }{ \cos^2x\sin^2x }\]

Skaematik
 2 years ago
Best ResponseYou've already chosen the best response.0Which part did you get stuck at

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0that equals \[\large\frac{ cosx+sinx }{ cosxsinx }\]

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0i can't seem to make them equal :(

Chlorophyll
 2 years ago
Best ResponseYou've already chosen the best response.11 + 2sinx cosx = sin²x + 2sinxcosx + cos²x = ( sinx + cosx)²

Chlorophyll
 2 years ago
Best ResponseYou've already chosen the best response.1cos²x  sin²x = ( cosx  sinx ) ( cosx + sinx)

Chlorophyll
 2 years ago
Best ResponseYou've already chosen the best response.1Now simplify upper and lower => the left side :)

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1353299245697:dw this right

Chlorophyll
 2 years ago
Best ResponseYou've already chosen the best response.1Can you simplify them?

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0yup, got it cosx+sinx/cosxsinx

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0LHS=RSH thankyou ! :D
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