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burhan101

  • 3 years ago

trig identity

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  1. burhan101
    • 3 years ago
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    \[\large \frac{ 1+2sinxcosx }{ \cos^2x-\sin^2x }\]

  2. Skaematik
    • 3 years ago
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    Which part did you get stuck at

  3. burhan101
    • 3 years ago
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    that equals \[\large\frac{ cosx+sinx }{ cosx-sinx }\]

  4. burhan101
    • 3 years ago
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    i can't seem to make them equal :(

  5. Chlorophyll
    • 3 years ago
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    1 + 2sinx cosx = sin²x + 2sinxcosx + cos²x = ( sinx + cosx)²

  6. Chlorophyll
    • 3 years ago
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    cos²x - sin²x = ( cosx - sinx ) ( cosx + sinx)

  7. Chlorophyll
    • 3 years ago
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    Now simplify upper and lower => the left side :)

  8. burhan101
    • 3 years ago
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    |dw:1353299245697:dw| this right

  9. Chlorophyll
    • 3 years ago
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    Can you simplify them?

  10. burhan101
    • 3 years ago
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    yup, got it cosx+sinx/cosx-sinx

  11. burhan101
    • 3 years ago
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    LHS=RSH thankyou ! :D

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