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Which formula based on partial derivatives provides the slope of the level curve z = f(x,y) ?

Calculus1
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I know the answer... But I don't know why.
What is the answer? Maybe it'll refresh my memory ^^ heh
I cant get the del sign in latex :/

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Other answers:

its ummm nambla i think.. \nambla
i thought it was \del
nabla*
i'll try :)
nope thats an upside down triangle
Yah that's the... del operator :o do you want the one with the vector arrow above it..? :o
\frac{ dy }{ dx } = -\frac{\del f /\del x}{\del f/\del y}
i mean like the one used on http://en.wikipedia.org/wiki/Partial_derivative
\[\partial \]
ahhh \partial
\[\Huge\frac{ dy }{ dx } = -\frac{\partial f /\partial x}{\partial f/\partial y}\]
\[\huge \vec \nabla f(x,y)=\left<\frac{\partial f}{\partial x}, \frac{\partial f}{\partial y}\right>\]
Oh sorry i didn't notice u already found it, hehe
oo, yours is fancy, i dont know what the nabla is though, thats okay...
Yah i been trying to figure out latex the last couple of weeks :) it's kinda interesting
very interesting.. i'm pressured to use it for one of my math classes, i try to avoid it.. :)
anyways, do you get the question?
the nabla thing is the "gradient" of f, it's the direction of greatest increase from a surface. It ummmmmm... i would try to draw a picture but i'm not sure i have the greatest understanding of it myself... :\ hmm
haha, thats okay.. i'll learn that when i get to that.

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