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kenneyfamily

  • 2 years ago

2/w + 3 > 29/w a. w > 9 b. w < 9 c. w < 0, w > 9 d. 0 < w < 9

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  1. campbell_st
    • 2 years ago
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    start by multiplying every term by w will leave 2 + 3w > 29 you should be able to solve it now..

  2. kenneyfamily
    • 2 years ago
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    but it has to be greater than zero right?

  3. kenneyfamily
    • 2 years ago
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    wait im confused

  4. campbell_st
    • 2 years ago
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    look at the solution provided by @ktnguyen1 he is saying w is less that 9 pick a value, say w =2 and substitute to check his solution 2/2 + 3 > 29/2 or 4 > 14.5 so the solution is incorrect...

  5. campbell_st
    • 2 years ago
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    if you multiply every term by w you get 2 +3w > 29 can you solve this...?

  6. kenneyfamily
    • 2 years ago
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    w=9

  7. kenneyfamily
    • 2 years ago
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    w>9

  8. campbell_st
    • 2 years ago
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    but he does also have a correct solution in his working... its just the way its written and your solution is correct... to test it pick w = 10 2/10 + 3 > 29/10 3.2 > 2.9 yes... so your solution is correct.

  9. kenneyfamily
    • 2 years ago
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    wait so is it a or c?

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