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\[25^{\log_{4}x }-5^{(\log _{16}x ^{2})+1}=\log _{\sqrt{3}}9\sqrt{3}-25^{\log _{16}x}\]

wow that's small

\[\Large{25^{\log_{4}x }-5^{(\log _{16}x ^{2})+1}=\log _{\sqrt{3}}9\sqrt{3}-25^{\log _{16}x}}\]

yes

What grade are you?

10th

doe that help solve the problem

No I just don't see how you can be doing these sort of things in grade 10

yeah me neither

Okay, I think x is 4, which makes the overall equation 0 = 0.

How did you realise it had to be a multiple of 4?

Makes a lot of sense.

How did you get to the second step lol

Ah I didn't think it would come out to be a whole number!! Great job on it.

Thanks @Skaematik :)