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can u give specific explaination of it, what like binomial do u mean ?

why not just use the formula to find the roots then sub in the values?

the quadratic equation formula

(-b(+-)root(b^2-4ac))/2a

no the sum of the roots is given by -b/a and product by c/a

yea, i know the quadratic equation formula.. but i dont think it will work

try using eulers substitution as the roots are complex..

hmm... yea, just look from the discriminant value it obvious, the roots are complexs