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AERONIK
 2 years ago
Best ResponseYou've already chosen the best response.0use binomial theorem and then use the expression for sum of the roots and the product of the roots for the quadratic. i think this should work out,

tanjung
 2 years ago
Best ResponseYou've already chosen the best response.0can u give specific explaination of it, what like binomial do u mean ?

irkiz
 2 years ago
Best ResponseYou've already chosen the best response.1why not just use the formula to find the roots then sub in the values?

irkiz
 2 years ago
Best ResponseYou've already chosen the best response.1the quadratic equation formula

AERONIK
 2 years ago
Best ResponseYou've already chosen the best response.0no the sum of the roots is given by b/a and product by c/a

tanjung
 2 years ago
Best ResponseYou've already chosen the best response.0yea, i know the quadratic equation formula.. but i dont think it will work

AERONIK
 2 years ago
Best ResponseYou've already chosen the best response.0try using eulers substitution as the roots are complex..

tanjung
 2 years ago
Best ResponseYou've already chosen the best response.0hmm... yea, just look from the discriminant value it obvious, the roots are complexs
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