anonymous
  • anonymous
Plane A which contains an isosceles right triangle forms a dihedral angle of 60 degrees with another plane B. if the hypotenuse of the triangle lies in plane B and measures 8 in., find the distance from the vertex of the right angle to plane B, and the length of the projection of each leg of the triangle on plane B.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
So, it's |dw:1353327509163:dw| and |dw:1353327558921:dw| Now, first we'll need to find the length of the hypotenuse and vertex of right angle. That's done by using the tan 45. Now, we'll find the distance from the vertex of the right angle to plane B. Since we have the length, which will be \(4 \tan 45^o\), we'll apply the sine to find that length. It will be |dw:1353327784152:dw| i.e. (4 tan 45)(sin 60)
anonymous
  • anonymous
Do you need further help?
anonymous
  • anonymous
wait.. i'm going to analyze it first

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More answers

anonymous
  • anonymous
find the distance from the vertex of the right angle to plane B = 4 square root of 3 length of the projection of each leg of the triangle on plane B = 8 is this correct?? regardless of the unit
anonymous
  • anonymous
the first might be 2 sqrt 3 the second..hmm can i see your workings?
anonymous
  • anonymous
aaaawwww.. i was wrong.... what i did was the 30-60-90 angles, but it should be 45-45-90.. right?
anonymous
  • anonymous
yup! :)
anonymous
  • anonymous
why 2 sqrt 3 ?? i got 2 sqrt 2
anonymous
  • anonymous
4 tan 45 = 4 4 sin 60 = 2 sqrt 3?
anonymous
  • anonymous
i don't get it T.T
anonymous
  • anonymous
lol for the first I find the length of d |dw:1353329595834:dw| to do this, i need |dw:1353329616295:dw|
anonymous
  • anonymous
please explain me this one "Plane A which contains an isosceles right triangle forms a dihedral angle of 60 degrees with another plane B." it's kinda confusing
anonymous
  • anonymous
It's the first pic. It means that the plane A is at angle of 60 with B
anonymous
  • anonymous
And on the plane A there is a isoscles right angle triangle.
anonymous
  • anonymous
|dw:1353387385535:dw| is it like this?? sorry for the drawing
anonymous
  • anonymous
Nice drawing. |dw:1353330325620:dw|
anonymous
  • anonymous
is that the right position of the isosceles triangle?
anonymous
  • anonymous
Yup. Since the "the hypotenuse of the triangle lies in plane B"
anonymous
  • anonymous
so where to put the imaginary line for this," from the vertex of the right angle to plane B" and "the length of the projection of each leg of the triangle on plane B."
anonymous
  • anonymous
and where is the 60 degree angle?? sorry if i have so many questions
anonymous
  • anonymous
|dw:1353330869441:dw| lol dun worry about it
anonymous
  • anonymous
|dw:1353330892217:dw|
anonymous
  • anonymous
where does projection of each leg of the triangle refers to??
anonymous
  • anonymous
I was thinking that they refer to the same line actually...because the triangles projection is really that point.
anonymous
  • anonymous
atlast i got it.. ahhaa.. thanks for the help!

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