MIT 6.002 Circuits and Electronics, Spring 2007
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
Just done Lab 12..Homework 12 later. R1=10 R2=2490 C1=0.0000001 C2=0.0000001
H12P1 A) Just V/i b) first find R2 = VS / i second the anwser is R = R2 - R1 (R1 is the awnser in a) c) I'm Trying LAB12 R1 (in Ohms): 1k C1 (in Farads): 1.59n R2 (in Ohms): 100k C2 (in Farads): 1.59n
HWP3 - first 5 filter: 10Hz and 19kHz. signals around 1kHz, to be amplified by about a factor of 2. 0.68μF and a 390pF capacitor. resistors between 100Ω and 100kΩ. RS=20kΩ. 1) First find C1=0.68*10^-6 = 6.8e-7 (answer of part 4) Then R1*C1=1/(2*pi*f) R1*C1=1/(2*pi*10) so R1= 23417 2)First find C2=390*10^-12 = 3.9e-10 (answer of part 5) R2*C2=1/(2*pi*19*10^3) R2= 21489 3) Rs = Rf = 20kΩ = 2000 Ω
Remaining answers HWP3 part 6 : R3= R1 part 7 : R4= R2 part 8: c3=c1 part 9 : c4= c2 part 9 :Midband gain = -(R4/R3)
some one asked me the value of pi. its always 3.14 buddy!
H12 P1 c) Q: v=5v A=100, load resistance =500 Solve two equations to find value of vx vx/R=(vOut–vx)/500,with R=answer from Part1. vx=5–vOut/100 Solving two equations we get Vx Current = Vx / R
hi mach.. i followed your method, since my variables are the same, but it gives me wrong answer!! can you check PLZ...
give me ur values !
what is the value of your vout machu ?
Write the answer for A=100, load 500 many errors when calculate this, because answer is in to within 0.1% of the exact answer
I'll be more clear with H12 P1 part c) my values are v=5v A=100, load resistance =500 First Solve two equations to find value of vx equation 1 : vx/R=(vOut–vx)/500,with R=answer from Part1. equation 2: vx=5–(vOut/100) Solving two equations we get Vx equation 1 :vout =1.5vx substitute the value of vout in equation 2 and u get vx Final Answer : Current = Vx/R
Thank you for H12P1 part c). After calculate my answer is 0.00883218771969
h12p2 ans plzzz
m nt getng rite ans frm this equatio...plz help mee out
Write your R1, v, A and load to calculate if problem in HP12P1 c). For H12P2 first two is a) vin*(R1+R2)/R2 b) vz*(R1+R2)/R2 for other 4 question I have too many work to calculate and do many error after 2-3 may be have time to give you answers.
HW12 QNo 2 Part 3 4 5 and r any help please
h12p2 part c,d..help
H12P2 a) vin*(R1+R2)/R2 b) vz*(R1+R2)/R2 c) 700 500 500 d) 0.15
H12P1: CURRENT SOURCE if A=100 v=5V, i=5mA ±VS=20V 500Ω within 0.1% of the exact What is ans of c=????
try 4.92/R R = first R (a)
For example, suppose that we need to put precisely i=8mA through a load that presents a resistance but the value of the resistance is not well controlled. Suppose also that we have a precision voltage source of v=5V, but this voltage source is pretty wimpy: it cannot supply more than 0.1mA without smoke coming out of it. With the circuit shown above we can choose a resistor of resistance R that can accomplish this goal. First, assuming that the op amp is ideal (A=∞) give the value of the resistance R, in Ohms, that we need.
Our specification is that we want there to be two break frequencies for this filter: 12Hz and 18kHz. We also want midband frequencies, such as signals around 1kHz, to be amplified by about a factor of 2. We have available a 1.2μF and a 390pF capacitor. We also have a variety of resistors between 100Ω and 100kΩ. However, our op amp really likes RS=20kΩ. Your job is to fill in the remaining details of this design.
i need answers for H12p2
H12P1: CURRENT SOURCE if A=100 v=5V, i=9mA ±VS=17V 500Ω within 0.1% of the exact. I got: a)555.555555556 b)1333.33333333 c) ??????? What is ans of c=????
any one did lab 12 please help how to calculate R1 C1 R2 C2