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eroshea

  • 3 years ago

From point A 10cm from a plane P, a perpendicular line AC is drawn passing through a circle with canter C and radius of 8 cm in the plane. At any point B on this circle, a tangent BD is drawn 18cm in length. FInd the distance from A to D. ----> i need the illustration

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  1. Shadowys
    • 3 years ago
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    |dw:1353418479537:dw|

  2. eroshea
    • 3 years ago
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    how can i solve this one?

  3. Shadowys
    • 3 years ago
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    well, you'll need to find CD. to do that, note that BDC is a right angle triangle.

  4. eroshea
    • 3 years ago
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    how does it became a right triangle?

  5. Shadowys
    • 3 years ago
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    CB and BD are given. so this calls for pythagoras theorem. Then also note that ADC is also a right angle triangle. AC is given, CD is found.

  6. Shadowys
    • 3 years ago
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    Well, since it is a tangent, tangents always meet the circle at right angles.

  7. eroshea
    • 3 years ago
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    |dw:1353476601742:dw| so the answer for AD is 22.1 cm??

  8. Shadowys
    • 3 years ago
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    yh. lol you've got it!

  9. eroshea
    • 3 years ago
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    thanks :))

  10. Shadowys
    • 3 years ago
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    you're welcome :)

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