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Jose.oliveira2Best ResponseYou've already chosen the best response.2
At the moment) H12P1 A) Just V/i b) first find R2 = VS / i second the anwser is R = R2  R1 (R1 is the awnser in a) c) I'm Trying LAB12 R1 (in Ohms): 1k C1 (in Farads): 1.59n R2 (in Ohms): 100k C2 (in Farads): 1.59n
 one year ago

TaimoorBest ResponseYou've already chosen the best response.0
Jose.oliveira2 R1 (in Ohms): 1k C1 (in Farads): 1.59n R2 (in Ohms): 100k C2 (in Farads): 1.59n These don't work can u upload the pic of ur opamp
 one year ago

AbhaypratapBest ResponseYou've already chosen the best response.0
R1=10 R2=2490 C1=0.0000001 C2=0.0000001
 one year ago

AbhaypratapBest ResponseYou've already chosen the best response.0
H12P3 a) ? b) ? c) 20000 d) 0.82u e) 390p f) ? g) ? h) 0.82u i) 390p j) ?
 one year ago

QaisersattiBest ResponseYou've already chosen the best response.1
Our specification is that we want there to be two break frequencies for this filter: 10Hz and 17kHz. We also want midband frequencies, such as signals around 1kHz, to be amplified by about a factor of 2. We have available a 1.8μF and a 220pF capacitor. We also have a variety of resistors between 100Ω and 100kΩ. However, our op amp really likes RS=20kΩ. Your job is to fill in the remaining details of this design. Q No 3 answers
 one year ago

machuBest ResponseYou've already chosen the best response.1
HWP3  first 5 filter: 10Hz and 19kHz. signals around 1kHz, to be amplified by about a factor of 2. 0.68μF and a 390pF capacitor. resistors between 100Ω and 100kΩ. RS=20kΩ. 1) First find C1=0.68*10^6 = 6.8e7 (answer of part 4) Then R1*C1=1/(2*pi*f) R1*C1=1/(2*pi*10) so R1= 23417 2)First find C2=390*10^12 = 3.9e10 (answer of part 5) R2*C2=1/(2*pi*19*10^3) R2= 21489 3) Rs = Rf = 20kΩ = 2000 Ω
 one year ago

machuBest ResponseYou've already chosen the best response.1
Remaining answers HWP3 part 6 : R3= R1 part 7 : R4= R2 part 8: c3=c1 part 9 : c4= c2 part 9 :Midband gain = (R4/R3)
 one year ago

machuBest ResponseYou've already chosen the best response.1
some one asked me the value of pi. its always 3.14 buddy!
 one year ago

machuBest ResponseYou've already chosen the best response.1
H12 P1 c) Q: v=5v A=100, load resistance =500 Solve two equations to find value of vx vx/R=(vOut–vx)/500,with R=answer from Part1. vx=5–vOut/100 Solving two equations we get Vx Current = Vx / R
 one year ago

brunofornariBest ResponseYou've already chosen the best response.0
@machu I did not undesrtand the c part of H12P1. I have these values: i=6mA A=100 R=833.333333333 VS=20V RL=500Ω
 one year ago

QaisersattiBest ResponseYou've already chosen the best response.1
what is ur value of v=?
 one year ago

QaisersattiBest ResponseYou've already chosen the best response.1
what is the value of R in u r part 1
 one year ago

QaisersattiBest ResponseYou've already chosen the best response.1
ok then do this 1.6vxvout=0 is your first equation 100vx+ vout=500 is your second equation add both will give u vx= 4.92 v i= 4.92/R=4.92/833.333= 0.005905512 this will be your answer please check yourself too.. tc and if correct click the best choice:) bye
 one year ago

brunofornariBest ResponseYou've already chosen the best response.0
worked.. tks, bro
 one year ago

brunofornariBest ResponseYou've already chosen the best response.0
I didn't do the H12P2.. did you already do?
 one year ago

Jose.oliveira2Best ResponseYou've already chosen the best response.2
H12P2 a) vin*(R1+R2)/2 b) vz*(R1+R2)/2 c? d? e? f? Have many problems with check. (BUG IN SYSTEM)
 one year ago

PapuashaBest ResponseYou've already chosen the best response.0
any one help H12P3 last question.................
 one year ago

AbhaypratapBest ResponseYou've already chosen the best response.0
use d formula above given by machu or gimme ur question :)
 one year ago
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