hi! i hope that somebody could help me. i can't understand why 0 < sin x< 1 on (0,π) if i put π/2 i get 1. could someone help me ?

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

hi! i hope that somebody could help me. i can't understand why 0 < sin x< 1 on (0,π) if i put π/2 i get 1. could someone help me ?

OCW Scholar - Single Variable Calculus
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

I’m not a math major, but I think I know the answer to this. Sine is modeled using a unit circle. That’s basically a circle drawn on an X and Y plane with the origin at (0,0) and a radius of 1. Since the radius is one, the largest value of x is when y=0 and the largest value of y is when x=0. You can see a unit circle and they talk about the nature of Sine here: http://www.youtube.com/watch?v=JPWVnpdfa0E We are primarily interested in the y axis since the will be opposite in the Sine formula of opposite/hypotenuse. From that graph, it’s pretty easy to see that the value of y is going to never be greater than 1 and never less than 0 for any angle between 0 and pi. Also, since y is always going to be less than the radius, it will be smaller than the hypotenuse which is the radius. A smaller number(x) divided by a bigger number 1(the radius) will be a fraction that is less than 1. However, it is possible for sin to be negative if the angles are greater than pi. At that point, y becomes negative which changes the sign of the result. The original problem was restricted between 0 and pi though, so that will not happen in the problem you stated. You can see this in a table of sin values here: http://www.grc.nasa.gov/WWW/k-12/airplane/tablsin.html It should be easy to see from that table that it is never greater than one or less than zero.
Oops. Disregard my previous post. I didn't read your question carefully enough. I think you are correct. The problem is wrong. It should be "0<= sin x<=1".
I believe the problem should state 0 < sinx <= 1 on (0,Pi). If you look at intervals the way we do then (0,Pi) is an open interval so you would never actually use 0 or Pi so the 0

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Not the answer you are looking for?

Search for more explanations.

Ask your own question