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adi171
 2 years ago
integrate : ( indefinite)
1 / sinx + secx
adi171
 2 years ago
integrate : ( indefinite) 1 / sinx + secx

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ikhwanz
 2 years ago
Best ResponseYou've already chosen the best response.1using 1/sinx + 1/cosx= cosx+sinx/sinx cosx then using sum and product rule sinx cosx =1/2 sin(2x)+sin(0)

RaGhavv
 2 years ago
Best ResponseYou've already chosen the best response.0Its 1/sinx + secx or 1/(sinx +secx)??

CogitoErgoAdd
 2 years ago
Best ResponseYou've already chosen the best response.0Integrate each term separately to get log(cosec(x)cotan(x)+log(tan(x)+sec(x)) If we assume the log arguments are positive and using the fact that log(a)+log(b)=log(a*b) we can transform this into log(1/sin(x)1/cos(x)/sin(x)1/cos(x)+1) I have attached an .xps (microsoft format) file with more details
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