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adi171

  • 3 years ago

integrate : ( indefinite) 1 / sinx + secx

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  1. ikhwanz
    • 3 years ago
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    using 1/sinx + 1/cosx= cosx+sinx/sinx cosx then using sum and product rule sinx cosx =1/2 sin(2x)+sin(0)

  2. RaGhavv
    • 3 years ago
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    Its 1/sinx + secx or 1/(sinx +secx)??

  3. CogitoErgoAdd
    • 3 years ago
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    Integrate each term separately to get log(|cosec(x)-cotan(x)|+log(|tan(x)+sec(x)|) If we assume the log arguments are positive and using the fact that log(a)+log(b)=log(a*b) we can transform this into log(1/sin(x)-1/cos(x)/sin(x)-1/cos(x)+1) I have attached an .xps (microsoft format) file with more details

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  4. adi171
    • 3 years ago
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    1/(sinx +secx)

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