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anonymous
 4 years ago
Okay I'm almost there but the answer I'm getting is incorrect.
anonymous
 4 years ago
Okay I'm almost there but the answer I'm getting is incorrect.

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\ln (x)+\ln (x2)=\ln 8\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then...\[\ln (x)(x2)=\ln 8\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then...\[\ln (x ^{2}2x)=\ln 8\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then drop the ln... \[x^{2}2x=8\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well you e^ both sides. That's how the ln cancel. But then you are left with a quadratic equation

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0split the two, \[x^{2}=8\] and \[2x=8\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0u need quadratic formula

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Compare your quadratic equation with \(ax^2+bx+c=0\) find a,b,c then the two roots of x are: \(\huge{x=\frac{b \pm \sqrt{b^24ac}}{2a}}\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay gimme a second to work that out.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0*** and need to remember to check for valid values of x. if you are taking ln(x) and ln(x2) what can't x be?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You can always complete the square. That's another way of solving this without the long work of using the quadratic

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0whats finishing the square? Sounds like a shortcut I was denied...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0shortcut only if u have some prsctice.... u wanna learn that ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0... or just factor? \[x^22x8=0=(x?)(x+?)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0practice some more then use that form

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0factoring is best here..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'll give it a shot! :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0go han!!!! go ku!!!! dominate the problem TEAMWORKKKK

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[x^2−2x−8=0=(x−A)(x+B)\\ A*B=8\\ A+B=2\] Find A and B

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You have a system of question where you can simply plug in one equation to another if you can't see it right away. Then solve for the missing variable.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so what are 2 values of x u got ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ten solving its 4 and 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and 2 would be extraneous

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but can x be 2 ?? think ....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes, so x is only = ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0THanks everyone! I really appreciate it! :)
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