anonymous
  • anonymous
Okay I'm almost there but the answer I'm getting is incorrect.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[\ln (x)+\ln (x-2)=\ln 8\]
anonymous
  • anonymous
then...\[\ln (x)(x-2)=\ln 8\]
anonymous
  • anonymous
then...\[\ln (x ^{2}-2x)=\ln 8\]

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anonymous
  • anonymous
then drop the ln... \[x^{2}-2x=8\]
anonymous
  • anonymous
going good...
anonymous
  • anonymous
well you e^ both sides. That's how the ln cancel. But then you are left with a quadratic equation
anonymous
  • anonymous
split the two, \[x^{2}=8\] and \[-2x=8\]
anonymous
  • anonymous
thats incorrect
anonymous
  • anonymous
true ok ok
anonymous
  • anonymous
u need quadratic formula
anonymous
  • anonymous
yup
anonymous
  • anonymous
Compare your quadratic equation with \(ax^2+bx+c=0\) find a,b,c then the two roots of x are: \(\huge{x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)
anonymous
  • anonymous
x^2-2x-8=0
anonymous
  • anonymous
okay gimme a second to work that out.
anonymous
  • anonymous
sure.
anonymous
  • anonymous
*** and need to remember to check for valid values of x. if you are taking ln(x) and ln(x-2) what can't x be?
anonymous
  • anonymous
You can always complete the square. That's another way of solving this without the long work of using the quadratic
anonymous
  • anonymous
2
anonymous
  • anonymous
whats finishing the square? Sounds like a shortcut I was denied...
anonymous
  • anonymous
granted
anonymous
  • anonymous
shortcut only if u have some prsctice.... u wanna learn that ?
anonymous
  • anonymous
... or just factor? \[x^2-2x-8=0=(x-?)(x+?)\]
anonymous
  • anonymous
practice some more then use that form
anonymous
  • anonymous
factoring is best here..
anonymous
  • anonymous
can u factor ?
anonymous
  • anonymous
I'll give it a shot! :)
anonymous
  • anonymous
sure do :)
anonymous
  • anonymous
go han!!!! go ku!!!! dominate the problem TEAMWORKKKK
anonymous
  • anonymous
? jerry ?
anonymous
  • anonymous
GO HAN GO KU
anonymous
  • anonymous
\[x^2−2x−8=0=(x−A)(x+B)\\ A*B=-8\\ A+B=-2\] Find A and B
anonymous
  • anonymous
Almost there....
anonymous
  • anonymous
You have a system of question where you can simply plug in one equation to another if you can't see it right away. Then solve for the missing variable.
anonymous
  • anonymous
its (x-4)(x+2)
anonymous
  • anonymous
thats correct :)
anonymous
  • anonymous
so what are 2 values of x u got ?
anonymous
  • anonymous
ten solving its 4 and -2
anonymous
  • anonymous
\[(x-4)(x+2)=0\]
anonymous
  • anonymous
and -2 would be extraneous
anonymous
  • anonymous
but can x be -2 ?? think ....
anonymous
  • anonymous
yes, so x is only = ?
anonymous
  • anonymous
4?
anonymous
  • anonymous
yup, u got it :)
anonymous
  • anonymous
HAZUAHH!
anonymous
  • anonymous
THanks everyone! I really appreciate it! :)
anonymous
  • anonymous
welcome ^_^

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