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natnatwebb
Group Title
Okay I'm almost there but the answer I'm getting is incorrect.
 one year ago
 one year ago
natnatwebb Group Title
Okay I'm almost there but the answer I'm getting is incorrect.
 one year ago
 one year ago

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natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
\[\ln (x)+\ln (x2)=\ln 8\]
 one year ago

natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
then...\[\ln (x)(x2)=\ln 8\]
 one year ago

natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
then...\[\ln (x ^{2}2x)=\ln 8\]
 one year ago

natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
then drop the ln... \[x^{2}2x=8\]
 one year ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
going good...
 one year ago

RyanL. Group TitleBest ResponseYou've already chosen the best response.0
well you e^ both sides. That's how the ln cancel. But then you are left with a quadratic equation
 one year ago

natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
split the two, \[x^{2}=8\] and \[2x=8\]
 one year ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
thats incorrect
 one year ago

Jerry123gnzcraft Group TitleBest ResponseYou've already chosen the best response.0
true ok ok
 one year ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
u need quadratic formula
 one year ago

Jerry123gnzcraft Group TitleBest ResponseYou've already chosen the best response.0
yup
 one year ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
Compare your quadratic equation with \(ax^2+bx+c=0\) find a,b,c then the two roots of x are: \(\huge{x=\frac{b \pm \sqrt{b^24ac}}{2a}}\)
 one year ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
x^22x8=0
 one year ago

natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
okay gimme a second to work that out.
 one year ago

freewilly922 Group TitleBest ResponseYou've already chosen the best response.0
*** and need to remember to check for valid values of x. if you are taking ln(x) and ln(x2) what can't x be?
 one year ago

RyanL. Group TitleBest ResponseYou've already chosen the best response.0
You can always complete the square. That's another way of solving this without the long work of using the quadratic
 one year ago

natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
whats finishing the square? Sounds like a shortcut I was denied...
 one year ago

Jerry123gnzcraft Group TitleBest ResponseYou've already chosen the best response.0
granted
 one year ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
shortcut only if u have some prsctice.... u wanna learn that ?
 one year ago

freewilly922 Group TitleBest ResponseYou've already chosen the best response.0
... or just factor? \[x^22x8=0=(x?)(x+?)\]
 one year ago

Jerry123gnzcraft Group TitleBest ResponseYou've already chosen the best response.0
practice some more then use that form
 one year ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
factoring is best here..
 one year ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
can u factor ?
 one year ago

natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
I'll give it a shot! :)
 one year ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
sure do :)
 one year ago

Jerry123gnzcraft Group TitleBest ResponseYou've already chosen the best response.0
go han!!!! go ku!!!! dominate the problem TEAMWORKKKK
 one year ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
? jerry ?
 one year ago

Jerry123gnzcraft Group TitleBest ResponseYou've already chosen the best response.0
GO HAN GO KU
 one year ago

RyanL. Group TitleBest ResponseYou've already chosen the best response.0
\[x^2−2x−8=0=(x−A)(x+B)\\ A*B=8\\ A+B=2\] Find A and B
 one year ago

natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
Almost there....
 one year ago

RyanL. Group TitleBest ResponseYou've already chosen the best response.0
You have a system of question where you can simply plug in one equation to another if you can't see it right away. Then solve for the missing variable.
 one year ago

natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
its (x4)(x+2)
 one year ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
thats correct :)
 one year ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
so what are 2 values of x u got ?
 one year ago

natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
ten solving its 4 and 2
 one year ago

RyanL. Group TitleBest ResponseYou've already chosen the best response.0
\[(x4)(x+2)=0\]
 one year ago

natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
and 2 would be extraneous
 one year ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
but can x be 2 ?? think ....
 one year ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
yes, so x is only = ?
 one year ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
yup, u got it :)
 one year ago

natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
HAZUAHH!
 one year ago

natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
THanks everyone! I really appreciate it! :)
 one year ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
welcome ^_^
 one year ago
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