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natnatwebb
Group Title
Okay I'm almost there but the answer I'm getting is incorrect.
 2 years ago
 2 years ago
natnatwebb Group Title
Okay I'm almost there but the answer I'm getting is incorrect.
 2 years ago
 2 years ago

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natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
\[\ln (x)+\ln (x2)=\ln 8\]
 2 years ago

natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
then...\[\ln (x)(x2)=\ln 8\]
 2 years ago

natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
then...\[\ln (x ^{2}2x)=\ln 8\]
 2 years ago

natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
then drop the ln... \[x^{2}2x=8\]
 2 years ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
going good...
 2 years ago

RyanL. Group TitleBest ResponseYou've already chosen the best response.0
well you e^ both sides. That's how the ln cancel. But then you are left with a quadratic equation
 2 years ago

natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
split the two, \[x^{2}=8\] and \[2x=8\]
 2 years ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
thats incorrect
 2 years ago

Jerry123gnzcraft Group TitleBest ResponseYou've already chosen the best response.0
true ok ok
 2 years ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
u need quadratic formula
 2 years ago

Jerry123gnzcraft Group TitleBest ResponseYou've already chosen the best response.0
yup
 2 years ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
Compare your quadratic equation with \(ax^2+bx+c=0\) find a,b,c then the two roots of x are: \(\huge{x=\frac{b \pm \sqrt{b^24ac}}{2a}}\)
 2 years ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
x^22x8=0
 2 years ago

natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
okay gimme a second to work that out.
 2 years ago

freewilly922 Group TitleBest ResponseYou've already chosen the best response.0
*** and need to remember to check for valid values of x. if you are taking ln(x) and ln(x2) what can't x be?
 2 years ago

RyanL. Group TitleBest ResponseYou've already chosen the best response.0
You can always complete the square. That's another way of solving this without the long work of using the quadratic
 2 years ago

natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
whats finishing the square? Sounds like a shortcut I was denied...
 2 years ago

Jerry123gnzcraft Group TitleBest ResponseYou've already chosen the best response.0
granted
 2 years ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
shortcut only if u have some prsctice.... u wanna learn that ?
 2 years ago

freewilly922 Group TitleBest ResponseYou've already chosen the best response.0
... or just factor? \[x^22x8=0=(x?)(x+?)\]
 2 years ago

Jerry123gnzcraft Group TitleBest ResponseYou've already chosen the best response.0
practice some more then use that form
 2 years ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
factoring is best here..
 2 years ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
can u factor ?
 2 years ago

natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
I'll give it a shot! :)
 2 years ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
sure do :)
 2 years ago

Jerry123gnzcraft Group TitleBest ResponseYou've already chosen the best response.0
go han!!!! go ku!!!! dominate the problem TEAMWORKKKK
 2 years ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
? jerry ?
 2 years ago

Jerry123gnzcraft Group TitleBest ResponseYou've already chosen the best response.0
GO HAN GO KU
 2 years ago

RyanL. Group TitleBest ResponseYou've already chosen the best response.0
\[x^2−2x−8=0=(x−A)(x+B)\\ A*B=8\\ A+B=2\] Find A and B
 2 years ago

natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
Almost there....
 2 years ago

RyanL. Group TitleBest ResponseYou've already chosen the best response.0
You have a system of question where you can simply plug in one equation to another if you can't see it right away. Then solve for the missing variable.
 2 years ago

natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
its (x4)(x+2)
 2 years ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
thats correct :)
 2 years ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
so what are 2 values of x u got ?
 2 years ago

natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
ten solving its 4 and 2
 2 years ago

RyanL. Group TitleBest ResponseYou've already chosen the best response.0
\[(x4)(x+2)=0\]
 2 years ago

natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
and 2 would be extraneous
 2 years ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
but can x be 2 ?? think ....
 2 years ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
yes, so x is only = ?
 2 years ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
yup, u got it :)
 2 years ago

natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
HAZUAHH!
 2 years ago

natnatwebb Group TitleBest ResponseYou've already chosen the best response.0
THanks everyone! I really appreciate it! :)
 2 years ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.2
welcome ^_^
 2 years ago
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