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Find the Inverse of the function: f(x)= (x/6)^3 - 7 My answer was f^-1(x) = 6(x+7)^3 is this correct?

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You exponent is incorrect.
so would i write it like this? f^-1(x) = [6(x+7)]3
ohhh or is it f^-1(x) = 6(x^3 + 7)?

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Other answers:

No, what you did wrong was to assume that \[(y/6)^3 =x+7 \to y/6=(x+7)^3\] That's not how you get rid of exponents. if \[y^4=x\to y=x^{1/4}\]
okay, so it should be f-1(x) = 18(x + 7) then? Thats the only other answer i got...
You first answer was correct EXCEPT the actual number you put in the exponent. if you had \[y=(x/2)^3-1\] then to find the inverse swap x and y and solve \[x=(y/2)^3-1\] then \[x+1=(y/2)^3\] this is where you did something weird. Where I would take the 1/3 root of both sides: \[(x+2)^{1/3} = ((y/2)^3)^{\frac{1}{3}}=y\] you took both sides to the third power.
Oh okay, i see what i types wrong...thank you so much!
Good luck!

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