I have initial problem
I solved it and I got that it's solution is
In book, there's written that the solution exists only in the interval −∞ < t < 1. Why? Why not in
1< t < ∞ too?
Stacey Warren - Expert brainly.com
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dy/dx = y^2
y^-2 dy = dx ; y!= 0
-y^-1 = x + C ; y!= 0
-y^-1 = x + C ; C = -1
y = 1/(-x+1)
since there is a split in the domain; and x=0 is only in the left side of the domain; then the initial value does not exist in the right side of the domain
something to do with continuity we have to split the function into 2 parts; each one being continuous in its own right i believe
i think its because the initial value y(0)=1is on the left side of the graph, since you are dealing only on the half left side of the graph,,,try to graph this one and you will see it