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babystar16
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if 8 pens and 7 pencils cost $3.37 while 5 pens and 11 pencils cost $3.10, how much does each pen and pencil cost?
 one year ago
 one year ago
babystar16 Group Title
if 8 pens and 7 pencils cost $3.37 while 5 pens and 11 pencils cost $3.10, how much does each pen and pencil cost?
 one year ago
 one year ago

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MathLegend Group TitleBest ResponseYou've already chosen the best response.1
@babystar16 do you want me to show you how to solve?
 one year ago

babystar16 Group TitleBest ResponseYou've already chosen the best response.1
plzzzzzzzzzzzzzzz
 one year ago

MathLegend Group TitleBest ResponseYou've already chosen the best response.1
So we can setup system of linear equation.
 one year ago

MathLegend Group TitleBest ResponseYou've already chosen the best response.1
P = Pens C = Pencils
 one year ago

MathLegend Group TitleBest ResponseYou've already chosen the best response.1
8p+7c=3.37 5p+11c=3.10
 one year ago

MathLegend Group TitleBest ResponseYou've already chosen the best response.1
@babystar16 can't we multiply both of the 'p' variables to get a common number? Lets multiply the 8p times 5. Then the 5p times 8.
 one year ago

MathLegend Group TitleBest ResponseYou've already chosen the best response.1
40p35c=16.85 40p+88c=24.80  (Now, we add...) 53c = 7.95 c = .15
 one year ago

MathLegend Group TitleBest ResponseYou've already chosen the best response.1
@babystar16 do you understand this?
 one year ago

MathLegend Group TitleBest ResponseYou've already chosen the best response.1
Now, just plug back in .15 for c in the original equation.
 one year ago

MathLegend Group TitleBest ResponseYou've already chosen the best response.1
5p+11(.15)=3.10 5p + 1.65 = 3.10 5p = 1.45 p = .29
 one year ago

MathLegend Group TitleBest ResponseYou've already chosen the best response.1
Pens were .29 cent Pencils were .15 cent
 one year ago

babystar16 Group TitleBest ResponseYou've already chosen the best response.1
thank u
 one year ago

babystar16 Group TitleBest ResponseYou've already chosen the best response.1
thank u for helping me understand it
 one year ago
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