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babystar16

  • 3 years ago

if 8 pens and 7 pencils cost $3.37 while 5 pens and 11 pencils cost $3.10, how much does each pen and pencil cost?

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  1. MathLegend
    • 3 years ago
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    @babystar16 do you want me to show you how to solve?

  2. babystar16
    • 3 years ago
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    plzzzzzzzzzzzzzzz

  3. MathLegend
    • 3 years ago
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    So we can setup system of linear equation.

  4. MathLegend
    • 3 years ago
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    P = Pens C = Pencils

  5. MathLegend
    • 3 years ago
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    8p+7c=3.37 5p+11c=3.10

  6. MathLegend
    • 3 years ago
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    @babystar16 can't we multiply both of the 'p' variables to get a common number? Lets multiply the 8p times -5. Then the 5p times 8.

  7. MathLegend
    • 3 years ago
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    -40p-35c=-16.85 40p+88c=24.80 ------------------ (Now, we add...) 53c = 7.95 c = .15

  8. MathLegend
    • 3 years ago
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    @babystar16 do you understand this?

  9. MathLegend
    • 3 years ago
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    Now, just plug back in .15 for c in the original equation.

  10. MathLegend
    • 3 years ago
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    5p+11(.15)=3.10 5p + 1.65 = 3.10 5p = 1.45 p = .29

  11. MathLegend
    • 3 years ago
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    Pens were .29 cent Pencils were .15 cent

  12. babystar16
    • 3 years ago
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    thank u

  13. babystar16
    • 3 years ago
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    thank u for helping me understand it

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