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satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1\[x^2+2x7=0\]add 7 \[x^2+2x=7\] take half of 2, which is 1 and write \[(x+1)^2=7+1^2=8\] take the square root, don't forget the \(\pm\) and write \[x+1=\pm\sqrt{8}\] subtract 1 get \[x=1\pm\sqrt{8}\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1you can rewrite in simplest radical form as \[x=1\pm2\sqrt{2}\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1second one is similar \[x^2+6x+10=0\]start by multiplying by \(1\) to get \[x^26x10=0\] add 10 get \[x^26x=10\]half of \(6\) is \(3\) \[(x3)^2=10+6^2=46\] take the square root \[x3=\pm\sqrt{46}\] add 3 \[x=3\pm\sqrt{46}\]
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