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 2 years ago
Solve the equation on the interval [0, 2π).
sin^2x  cos^2x = 0
A. π/4
B. π/4 ; π/6
C. π/4 ; π/3
D. π/4 ; 3π/4 ; 5π/4 ; 7π/4
 2 years ago
Solve the equation on the interval [0, 2π). sin^2x  cos^2x = 0 A. π/4 B. π/4 ; π/6 C. π/4 ; π/3 D. π/4 ; 3π/4 ; 5π/4 ; 7π/4

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satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1D should work since \(\sin^2(x)=\cos^2(x)\) means \(\sin(x)=\pm\cos(x)\)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1at all those numbers you get \(\pm\frac{\sqrt{2}}{2}\) for sine and cosine
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