Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

alyssababy7

  • 3 years ago

Solve the equation on the interval [0, 2π). sin^2x - cos^2x = 0 A. π/4 B. π/4 ; π/6 C. π/4 ; π/3 D. π/4 ; 3π/4 ; 5π/4 ; 7π/4

  • This Question is Closed
  1. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    D should work since \(\sin^2(x)=\cos^2(x)\) means \(\sin(x)=\pm\cos(x)\)

  2. alyssababy7
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Thank you!

  3. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    at all those numbers you get \(\pm\frac{\sqrt{2}}{2}\) for sine and cosine

  4. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yw

  5. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy