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alyssababy7
Group Title
Solve the equation on the interval [0, 2π).
sin^2x  cos^2x = 0
A. π/4
B. π/4 ; π/6
C. π/4 ; π/3
D. π/4 ; 3π/4 ; 5π/4 ; 7π/4
 one year ago
 one year ago
alyssababy7 Group Title
Solve the equation on the interval [0, 2π). sin^2x  cos^2x = 0 A. π/4 B. π/4 ; π/6 C. π/4 ; π/3 D. π/4 ; 3π/4 ; 5π/4 ; 7π/4
 one year ago
 one year ago

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satellite73 Group TitleBest ResponseYou've already chosen the best response.1
D should work since \(\sin^2(x)=\cos^2(x)\) means \(\sin(x)=\pm\cos(x)\)
 one year ago

alyssababy7 Group TitleBest ResponseYou've already chosen the best response.0
Thank you!
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
at all those numbers you get \(\pm\frac{\sqrt{2}}{2}\) for sine and cosine
 one year ago
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