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alyssababy7

  • 3 years ago

Solve the equation on the interval [0, 2π). cos x + 2 cos x sin x = 0 A. 0 ; π/2 ; 7π/6 ; 3π/2 B. π/2 ; 7π/6 ; 3π/2 ; 11π/6 C. 7π/6 ; 11π/6 ; 2n D. 7π/6 ; 11π/6

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  1. Brittni0605
    • 3 years ago
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    Do you need step by step help or just guidance?

  2. anonymous
    • 3 years ago
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    \[\cos(x)(1+2\sin(x))=0\] \[\cos(x)=0\implies x=\frac{\pi}{2},x=\frac{3\pi}{2}\]or \[1+\sin(x)=0\implies \sin(x)=\frac{1}{2}\]etc

  3. alyssababy7
    • 3 years ago
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    would it be B

  4. Brittni0605
    • 3 years ago
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    Yes.

  5. alyssababy7
    • 3 years ago
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    thank you very much. i just get stuck in the first steps.

  6. Brittni0605
    • 3 years ago
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    Ok, np.

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