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anonymous
 3 years ago
Solve the equation on the interval [0, 2π).
cos x + 2 cos x sin x = 0
A. 0 ; π/2 ; 7π/6 ; 3π/2
B. π/2 ; 7π/6 ; 3π/2 ; 11π/6
C. 7π/6 ; 11π/6 ; 2n
D. 7π/6 ; 11π/6
anonymous
 3 years ago
Solve the equation on the interval [0, 2π). cos x + 2 cos x sin x = 0 A. 0 ; π/2 ; 7π/6 ; 3π/2 B. π/2 ; 7π/6 ; 3π/2 ; 11π/6 C. 7π/6 ; 11π/6 ; 2n D. 7π/6 ; 11π/6

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Do you need step by step help or just guidance?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\cos(x)(1+2\sin(x))=0\] \[\cos(x)=0\implies x=\frac{\pi}{2},x=\frac{3\pi}{2}\]or \[1+\sin(x)=0\implies \sin(x)=\frac{1}{2}\]etc

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thank you very much. i just get stuck in the first steps.
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