Here's the question you clicked on:
alyssababy7
Solve the equation on the interval [0, 2π). cos x + 2 cos x sin x = 0 A. 0 ; π/2 ; 7π/6 ; 3π/2 B. π/2 ; 7π/6 ; 3π/2 ; 11π/6 C. 7π/6 ; 11π/6 ; 2n D. 7π/6 ; 11π/6
Do you need step by step help or just guidance?
\[\cos(x)(1+2\sin(x))=0\] \[\cos(x)=0\implies x=\frac{\pi}{2},x=\frac{3\pi}{2}\]or \[1+\sin(x)=0\implies \sin(x)=\frac{1}{2}\]etc
thank you very much. i just get stuck in the first steps.