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anonymous
 4 years ago
Need Help!!! Please help! I need it badly!
10.04] Simplify the expression.
the square root of the quantity 27 x to the fifth power, plus x times the square root of 3, plus nine times the square root of the quantity 3x
If the simplified expression is written in standard form, what is the leading coefficient?
anonymous
 4 years ago
Need Help!!! Please help! I need it badly! 10.04] Simplify the expression. the square root of the quantity 27 x to the fifth power, plus x times the square root of 3, plus nine times the square root of the quantity 3x If the simplified expression is written in standard form, what is the leading coefficient?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Simplify this also, thx!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What? That isn't very helpful!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0OMG ! Does nobody know this?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0√(27x^4) + x√(3) + 9√(3x) Complete the squares to get.. 3x²√(3) + x√(3) + 9√(3x) = (3x² + x)√(3) + 9√(3x)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What is the leading coefficient?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I gave you all the help I can give for now because you're not suppose to give answers just plug in all the numbers that I gave you and you'll figure it out (: Good luck~

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0OK, um, can you tell me if I'm right, at least?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Or tell me what a coefficient is?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Because I don't know. :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Its a number that is used to multiply by a variable

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I suggest Khan Academy for a research tool it helped me alot (: www.khanacademy.org < Really good resource.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ch, I will check it out! That;s all I need to know. >:)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thx, it was kind iof u to help out! :D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I still need help with coefficents, but Im fine. :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ohh I answered your question about coefficients up there :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yup! Thx, I just need the coefiicent for the problem, I am checking.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If I know any better, I am going to say 3. :)
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