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baldymcgee6

  • 2 years ago

For what values of a and b is the following parametric function continuous? http://screencast.com/t/ydAe0nVzELd

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  1. baldymcgee6
    • 2 years ago
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    @hartnn

  2. baldymcgee6
    • 2 years ago
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    I have the solution, but i don't get it... Do you want me to post the solution?

  3. baldymcgee6
    • 2 years ago
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    http://screencast.com/t/C8XAD3vk1O

  4. hartnn
    • 2 years ago
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    which part u didn't get ? for limit to be continuous, u need to have lim x->0- ... = lim x->0+ ..

  5. baldymcgee6
    • 2 years ago
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    why at 0?

  6. hartnn
    • 2 years ago
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    because the point of dis-continuity can be 0 only... as the function behaves differently (different definition) before and after 0

  7. baldymcgee6
    • 2 years ago
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    because of the domain restrictions?

  8. hartnn
    • 2 years ago
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    u can say that, but mostly its because of t<=0 ..... t> 0 if it were t<=2..... t>2, then u would have checked at x=2

  9. hartnn
    • 2 years ago
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    *t=2

  10. baldymcgee6
    • 2 years ago
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    okay... how does a=b?

  11. hartnn
    • 2 years ago
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    because , for continuity , lim x->0- needs to be equal to x->0+ and lim x->0- was 1 so, x-> 0+ = a/b = 1

  12. baldymcgee6
    • 2 years ago
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    ohhhhh..

  13. baldymcgee6
    • 2 years ago
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    thank you again!

  14. hartnn
    • 2 years ago
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    welcome ^_^

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