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baldymcgee6
Group Title
For what values of a and b is the following parametric function continuous?
http://screencast.com/t/ydAe0nVzELd
 one year ago
 one year ago
baldymcgee6 Group Title
For what values of a and b is the following parametric function continuous? http://screencast.com/t/ydAe0nVzELd
 one year ago
 one year ago

This Question is Closed

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.1
@hartnn
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.1
I have the solution, but i don't get it... Do you want me to post the solution?
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.1
http://screencast.com/t/C8XAD3vk1O
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
which part u didn't get ? for limit to be continuous, u need to have lim x>0 ... = lim x>0+ ..
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.1
why at 0?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
because the point of discontinuity can be 0 only... as the function behaves differently (different definition) before and after 0
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.1
because of the domain restrictions?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
u can say that, but mostly its because of t<=0 ..... t> 0 if it were t<=2..... t>2, then u would have checked at x=2
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.1
okay... how does a=b?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
because , for continuity , lim x>0 needs to be equal to x>0+ and lim x>0 was 1 so, x> 0+ = a/b = 1
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.1
ohhhhh..
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.1
thank you again!
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
welcome ^_^
 one year ago
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