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twilaswift
 3 years ago
The graph of a function is shown here.
A coordinate plane shows five ordered pairs being plotted. From the origin, the first dot is zero units right and seven units up. The second dot is two units right and six units up. The third dot is four units right and five units up. The fourth dot is eight units right and three units up. The fifth dot is six units right and four units up.
Which ordered pair, when added to the graph, will keep the graph a function?
(4, 4)
(6,1)
(10, 2)
(2, 9)
twilaswift
 3 years ago
The graph of a function is shown here. A coordinate plane shows five ordered pairs being plotted. From the origin, the first dot is zero units right and seven units up. The second dot is two units right and six units up. The third dot is four units right and five units up. The fourth dot is eight units right and three units up. The fifth dot is six units right and four units up. Which ordered pair, when added to the graph, will keep the graph a function? (4, 4) (6,1) (10, 2) (2, 9)

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Ahsher97
 3 years ago
Best ResponseYou've already chosen the best response.0are all of those from the origin? or ontop of eachother

Mr.Me
 3 years ago
Best ResponseYou've already chosen the best response.0find the equation of the line then plug in the points

Mr.Me
 3 years ago
Best ResponseYou've already chosen the best response.0y=mx+b y intercept is 7 so b =7 slope=m= (y2y1)/(x2x1) use the points (0,7) and (2,6)

Mr.Me
 3 years ago
Best ResponseYou've already chosen the best response.0and y=1/2x+7 plug in the possible values into this equation to see if they are valid

Mr.Me
 3 years ago
Best ResponseYou've already chosen the best response.0example (4,4) y=1/2x+7 (4)=1/2(4)+7 4=2+7 4=5 this doesn't make sense so (4,4) is not the point we want contine in this fashion until you find a point that works
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