## JenniferSmart1 Group Title Why is kx=25N instead of -kx=25N? one year ago one year ago

1. JenniferSmart1 Group Title

2. JenniferSmart1 Group Title

@Outkast3r09

3. JenniferSmart1 Group Title

shouldn't F=-kx?

4. JenniferSmart1 Group Title

@CliffSedge ?

5. Outkast3r09 Group Title

Ahh this my physics teacher went over

6. JenniferSmart1 Group Title

cool! Now you can explain it to me :)

7. Outkast3r09 Group Title

the negative explains how that force is acting upon the spring

8. Outkast3r09 Group Title

it depends on the what you're trying to find

9. Outkast3r09 Group Title

if you're trying to find the force the spring is exerting on the mass or the mass exerting on the spring

10. JenniferSmart1 Group Title

Hmmm let's see|dw:1353379482698:dw|

11. Outkast3r09 Group Title

|dw:1353379572781:dw|

12. JenniferSmart1 Group Title

well I guess we're stretching to a certain length, so the first figure?

13. JenniferSmart1 Group Title

I mean the first figure you drew

14. Outkast3r09 Group Title

the figures are the same

15. Outkast3r09 Group Title

it depends on whether you're trying to find the length of the spring or the position of the mass

16. JenniferSmart1 Group Title

Uhm I think we want my figure because In your figure we have to consider the gravitational force and the restoring force. I don't think they want to consider the gravitational force

17. Outkast3r09 Group Title

18. Outkast3r09 Group Title

there is two ways this question can be answered 1) How long did the spring stretch from initial 2) What is the position of the mass after initial. They're the same thing

19. Outkast3r09 Group Title

so since it's asking for position of the mass it's this|dw:1353379915405:dw|

20. JenniferSmart1 Group Title

why is it positive? because it is going in the direction that we designated as positive?

21. Outkast3r09 Group Title

yes

22. Outkast3r09 Group Title

23. JenniferSmart1 Group Title

OH I see! |dw:1353380068540:dw| Like so?

24. JenniferSmart1 Group Title

Now I can say that F=kx

25. JenniferSmart1 Group Title

right?

26. JenniferSmart1 Group Title

no the other way around, I should probably make the restoring force positive...

27. Outkast3r09 Group Title

|dw:1353380229463:dw|

28. Outkast3r09 Group Title

yeah the picture they used was probably a free falling mass

29. Outkast3r09 Group Title

and saying that the sum of the force of gravity + any other force = F

30. JenniferSmart1 Group Title

Yeah that makes more sense. so they probably had up as positive and down as negative.

31. Outkast3r09 Group Title

yes but it really just depends on what you define it... if your teacher marks you wrong and your diagram says otherwise just clear it up with him

32. JenniferSmart1 Group Title

yep

33. JenniferSmart1 Group Title

so why is k(0.2) why 0.2? How did they come up with x=0.2?

34. JenniferSmart1 Group Title

never mind

35. JenniferSmart1 Group Title

LOL

36. JenniferSmart1 Group Title

that's the displacement haha

37. Outkast3r09 Group Title

yes the displacement will still be posive

38. JenniferSmart1 Group Title

hmm interesting: (this the DE part of my calc II book) $2\frac{d^2x}{dt^2}+128x=0 \text{ has the solution }x(t)=c_1cos8t+c_2sin8t$ yeah that's easier that doing it manually....

39. CliffSedge Group Title

It's convention to designate potential energy as negative. The reaction force of the spring is opposite the positive applied force.

40. CliffSedge Group Title

More clearly: The negative sign of F=-kx means that the spring force is opposite to the applied force on the spring.

41. JenniferSmart1 Group Title

potential energy as positive...the restorative force?

42. JenniferSmart1 Group Title

Yes that makes sense

43. JenniferSmart1 Group Title

I had to reread the last sentence you wrote several times, but it makes sense now

44. JenniferSmart1 Group Title

but where did they get the 8 in sin and cos 8t

45. CliffSedge Group Title

As others mentioned above, it's a sign convention. You define what direction you want to be positive and anything opposite to that is negative. The norm, though is to treat spring force as negative/opposite to any force acting *on* the spring.

46. CliffSedge Group Title

The 8 is based on the period of the spring - that is determined by the spring constant, k, and the attached mass.

47. CliffSedge Group Title

$$\large T=2\pi \sqrt{\frac{m}{k}}$$ T^-1 is the frequency of oscillation.

48. JenniferSmart1 Group Title

yep, sounds good. I googled it LOL $T=2\pi \sqrt{\frac mk}$

49. CliffSedge Group Title

The "8" in the cosine function usually goes by the name, omega, $$\large \omega$$. Might want to look that up too.

50. JenniferSmart1 Group Title

so the formula is $x(t)=c_1cosTt+c_2sinTt$

51. JenniferSmart1 Group Title

so T is $\omega$

52. CliffSedge Group Title

$$\large . . . cos(\omega t) . .$$ No, ω is related to T.

53. JenniferSmart1 Group Title

Oh $\omega=\sqrt{\frac km}$

54. CliffSedge Group Title

Right!

55. JenniferSmart1 Group Title

$x(t)=c_1cos\omega t+c_2sin\omega t$

56. CliffSedge Group Title

Yes, you can either derive that using the Diff.Eq. or look it up on a physics formula sheet. (Depends on if you are more mathematician or engineer ;-) )

57. JenniferSmart1 Group Title

leaning more towards engineering....physics formula sheet :P

58. JenniferSmart1 Group Title

omega doesn't seem to have units

59. CliffSedge Group Title

That would be my choice too, but know that the way the physicists got those formulas in the first place was to solve the DEs (or rather to get their math dept. grad students and TAs to do the solving for them..)

60. CliffSedge Group Title

omega should have units of s^-1, it's a frequency.

61. CliffSedge Group Title

Or .. is at least based on a frequency, something in the derivation might make the units cancel, but I'm pretty sure it's just the reciprocal of the time period, T.

62. JenniferSmart1 Group Title

63. JenniferSmart1 Group Title

according to my friend wiki

64. JenniferSmart1 Group Title

so s^-1 should be sufficient, i can leave the radians part out in my notation?

65. CliffSedge Group Title

Yes, because radians are dimensionless (it's derived from length ÷ length), that's what the 2π conversion factor is in there for.

66. JenniferSmart1 Group Title

Oh I see

67. JenniferSmart1 Group Title

why is c_2 zero? shouldn't it be ...so when we say$x(0)=8c_2 cos8t$ does that mean $0=8c_2 cos8t=8c_2cos(0)=8c_2(1)=c_2$ yep that seems right LOL

68. JenniferSmart1 Group Title

Thanks everyone!!!!