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What is the derivative of 4pi and why?

Calculus1
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0, because it's a constant.
I thought it was 2pi
Why do you think it'd be \(2\pi\)? Explain how you got to the conclusion.

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I am working on this problem right now dealing with Area. This is what it looks like: \[c^2\div2\pi \] and the answer books says the derivative is C/2pi
wait.....C^2/4pi
That's an entirely different problem. You actually have a variable, whose derivative is \(2C\), multiplying that by \(\frac{1}{4\pi}\) gives you: \[ \frac{2C}{4\pi}=\frac{C}{2\pi} \]. So, to answer your original question, yes: \[ \frac{d}{dC}4\pi=0 \]BUT: \[ \frac{d}{dC}\frac{C^2}{4\pi}=\frac{2C}{4\pi}=\frac{C}{2\pi} \]Which is different.
always remember that the derivative of constant function is 0 ( zero ) .. 4pi is constant function...

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