anonymous
  • anonymous
What is the derivative of 4pi and why?
Calculus1
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
0, because it's a constant.
anonymous
  • anonymous
I thought it was 2pi
anonymous
  • anonymous
Why do you think it'd be \(2\pi\)? Explain how you got to the conclusion.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
I am working on this problem right now dealing with Area. This is what it looks like: \[c^2\div2\pi \] and the answer books says the derivative is C/2pi
anonymous
  • anonymous
wait.....C^2/4pi
anonymous
  • anonymous
That's an entirely different problem. You actually have a variable, whose derivative is \(2C\), multiplying that by \(\frac{1}{4\pi}\) gives you: \[ \frac{2C}{4\pi}=\frac{C}{2\pi} \]. So, to answer your original question, yes: \[ \frac{d}{dC}4\pi=0 \]BUT: \[ \frac{d}{dC}\frac{C^2}{4\pi}=\frac{2C}{4\pi}=\frac{C}{2\pi} \]Which is different.
anonymous
  • anonymous
always remember that the derivative of constant function is 0 ( zero ) .. 4pi is constant function...

Looking for something else?

Not the answer you are looking for? Search for more explanations.