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\[12a ^{5}\2a ^{8}\] real problem

Just to be clear, is this what you mean?
\[\frac{12a^{5}}{2a^{8}}\]

yes

Okay, are you able to solve it *with* negative exponents?

I did not know how to make the line on here

\frac{top}{bottom}
Do that in the Equation editor, or within \[ and \ ]

nope it said do not use neg exponents and the 5 is -5 and the 8 is -8

Wait, are you saying it's to the power of -5 and -8?

Which is correctâ€”top or bottom?
\[\frac{12a^{5}}{2a^{8}}\]
\[\frac{12a^{-5}}{2a^{-8}}\]

bottom

Okay, great. And there are no brackets, right? It's not \((12a)^{-5}\)?

So, to start, are you able to simplify the equation?

right

Do you know how to simplify exponents?

As for your numeric constants, you just divide them (\(12 \div 2\))

ok so that will be -13

5-8

No, it's (-5) - (-8).

12/2 is 6 -5-(-8)=3

A double-negative is a positive (in math).

Good!

So what's your final answer?

6a\[6a ^3\]

Good!

do I do the samething if my problem has 12 x top and 8y bottom

You can simplify the numbers \(\Large{\frac{12}{8} = \frac{3}{2}}\), but that's all.

yes with -6 at the top and -10 at the bottom

Ahh, so:
\[\frac{12x^{-6}}{8y^{-10}}\]
Nope, all you can simplify in this case is 12/8.

3x,2y

Yes, with the same exponents.

so there isn't any steps to break it down because my teacher keep saying show your work

If they're different variables, you can't simplify them further.

\[\Large\frac{12x^{-6}}{8y^{-10}} \small\frac{\div 4}{\div 4}\]

ok