anonymous
  • anonymous
help!!! simplify do not use negative exponents in the answer 12a 5th power / 2a 8th power
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
\[12a ^{5}\2a ^{8}\] real problem
anonymous
  • anonymous
Just to be clear, is this what you mean? \[\frac{12a^{5}}{2a^{8}}\]
anonymous
  • anonymous
yes

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anonymous
  • anonymous
Okay, are you able to solve it *with* negative exponents?
anonymous
  • anonymous
I did not know how to make the line on here
anonymous
  • anonymous
\frac{top}{bottom} Do that in the Equation editor, or within \[ and \ ]
anonymous
  • anonymous
nope it said do not use neg exponents and the 5 is -5 and the 8 is -8
anonymous
  • anonymous
I know, but once we get to the final answer *with* negative exponents, we can get rid of them by re-writing the answer.
anonymous
  • anonymous
Wait, are you saying it's to the power of -5 and -8?
anonymous
  • anonymous
Which is correct—top or bottom? \[\frac{12a^{5}}{2a^{8}}\] \[\frac{12a^{-5}}{2a^{-8}}\]
anonymous
  • anonymous
bottom
anonymous
  • anonymous
Okay, great. And there are no brackets, right? It's not \((12a)^{-5}\)?
anonymous
  • anonymous
So, to start, are you able to simplify the equation?
anonymous
  • anonymous
right
anonymous
  • anonymous
I could not find an exmaple in the book like mines so one of the problems in the exercise is like my real problem i need help to figure it out so i can solve mines
anonymous
  • anonymous
Do you know how to simplify exponents?
anonymous
  • anonymous
When dividing like bases (in this case, \(a\)), you subtract the bottom exponent from the top. So, \(a^{(-5)-(-8)}\).
anonymous
  • anonymous
As for your numeric constants, you just divide them (\(12 \div 2\))
anonymous
  • anonymous
ok so that will be -13
anonymous
  • anonymous
5-8
anonymous
  • anonymous
No, it's (-5) - (-8).
anonymous
  • anonymous
12/2 is 6 -5-(-8)=3
anonymous
  • anonymous
A double-negative is a positive (in math).
anonymous
  • anonymous
Good!
anonymous
  • anonymous
So what's your final answer?
anonymous
  • anonymous
6a\[6a ^3\]
anonymous
  • anonymous
Good!
anonymous
  • anonymous
do I do the samething if my problem has 12 x top and 8y bottom
anonymous
  • anonymous
Do you mean like: \(\Large{\frac{12x}{8y}}\) ? No, those are different variables, so you cannot divide one by the other.
anonymous
  • anonymous
You can simplify the numbers \(\Large{\frac{12}{8} = \frac{3}{2}}\), but that's all.
anonymous
  • anonymous
yes with -6 at the top and -10 at the bottom
anonymous
  • anonymous
Ahh, so: \[\frac{12x^{-6}}{8y^{-10}}\] Nope, all you can simplify in this case is 12/8.
anonymous
  • anonymous
3x,2y
anonymous
  • anonymous
Yes, with the same exponents.
anonymous
  • anonymous
so there isn't any steps to break it down because my teacher keep saying show your work
anonymous
  • anonymous
If they're different variables, you can't simplify them further.
anonymous
  • anonymous
The only "work" you could show is dividing both the top and bottom by 4, to simplify your numeric fraction.
anonymous
  • anonymous
\[\Large\frac{12x^{-6}}{8y^{-10}} \small\frac{\div 4}{\div 4}\]
anonymous
  • anonymous
ok

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