help!!! simplify do not use negative exponents in the answer 12a 5th power / 2a 8th power

- anonymous

help!!! simplify do not use negative exponents in the answer 12a 5th power / 2a 8th power

- katieb

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- anonymous

\[12a ^{5}\2a ^{8}\] real problem

- anonymous

Just to be clear, is this what you mean?
\[\frac{12a^{5}}{2a^{8}}\]

- anonymous

yes

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## More answers

- anonymous

Okay, are you able to solve it *with* negative exponents?

- anonymous

I did not know how to make the line on here

- anonymous

\frac{top}{bottom}
Do that in the Equation editor, or within \[ and \ ]

- anonymous

nope it said do not use neg exponents and the 5 is -5 and the 8 is -8

- anonymous

I know, but once we get to the final answer *with* negative exponents, we can get rid of them by re-writing the answer.

- anonymous

Wait, are you saying it's to the power of -5 and -8?

- anonymous

Which is correctâ€”top or bottom?
\[\frac{12a^{5}}{2a^{8}}\]
\[\frac{12a^{-5}}{2a^{-8}}\]

- anonymous

bottom

- anonymous

Okay, great. And there are no brackets, right? It's not \((12a)^{-5}\)?

- anonymous

So, to start, are you able to simplify the equation?

- anonymous

right

- anonymous

I could not find an exmaple in the book like mines so one of the problems in the exercise is like my real problem i need help to figure it out so i can solve mines

- anonymous

Do you know how to simplify exponents?

- anonymous

When dividing like bases (in this case, \(a\)), you subtract the bottom exponent from the top. So, \(a^{(-5)-(-8)}\).

- anonymous

As for your numeric constants, you just divide them (\(12 \div 2\))

- anonymous

ok so that will be -13

- anonymous

5-8

- anonymous

No, it's (-5) - (-8).

- anonymous

12/2 is 6 -5-(-8)=3

- anonymous

A double-negative is a positive (in math).

- anonymous

Good!

- anonymous

So what's your final answer?

- anonymous

6a\[6a ^3\]

- anonymous

Good!

- anonymous

do I do the samething if my problem has 12 x top and 8y bottom

- anonymous

Do you mean like: \(\Large{\frac{12x}{8y}}\) ?
No, those are different variables, so you cannot divide one by the other.

- anonymous

You can simplify the numbers \(\Large{\frac{12}{8} = \frac{3}{2}}\), but that's all.

- anonymous

yes with -6 at the top and -10 at the bottom

- anonymous

Ahh, so:
\[\frac{12x^{-6}}{8y^{-10}}\]
Nope, all you can simplify in this case is 12/8.

- anonymous

3x,2y

- anonymous

Yes, with the same exponents.

- anonymous

so there isn't any steps to break it down because my teacher keep saying show your work

- anonymous

If they're different variables, you can't simplify them further.

- anonymous

The only "work" you could show is dividing both the top and bottom by 4, to simplify your numeric fraction.

- anonymous

\[\Large\frac{12x^{-6}}{8y^{-10}} \small\frac{\div 4}{\div 4}\]

- anonymous

ok

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