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skylar87

help!!! simplify do not use negative exponents in the answer 12a 5th power / 2a 8th power

  • one year ago
  • one year ago

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  1. skylar87
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    \[12a ^{5}\2a ^{8}\] real problem

    • one year ago
  2. geoffb
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    Just to be clear, is this what you mean? \[\frac{12a^{5}}{2a^{8}}\]

    • one year ago
  3. skylar87
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    yes

    • one year ago
  4. geoffb
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    Okay, are you able to solve it *with* negative exponents?

    • one year ago
  5. skylar87
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    I did not know how to make the line on here

    • one year ago
  6. geoffb
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    \frac{top}{bottom} Do that in the Equation editor, or within \[ and \ ]

    • one year ago
  7. skylar87
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    nope it said do not use neg exponents and the 5 is -5 and the 8 is -8

    • one year ago
  8. geoffb
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    I know, but once we get to the final answer *with* negative exponents, we can get rid of them by re-writing the answer.

    • one year ago
  9. geoffb
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    Wait, are you saying it's to the power of -5 and -8?

    • one year ago
  10. geoffb
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    Which is correct—top or bottom? \[\frac{12a^{5}}{2a^{8}}\] \[\frac{12a^{-5}}{2a^{-8}}\]

    • one year ago
  11. skylar87
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    bottom

    • one year ago
  12. geoffb
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    Okay, great. And there are no brackets, right? It's not \((12a)^{-5}\)?

    • one year ago
  13. geoffb
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    So, to start, are you able to simplify the equation?

    • one year ago
  14. skylar87
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    right

    • one year ago
  15. skylar87
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    I could not find an exmaple in the book like mines so one of the problems in the exercise is like my real problem i need help to figure it out so i can solve mines

    • one year ago
  16. geoffb
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    Do you know how to simplify exponents?

    • one year ago
  17. geoffb
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    When dividing like bases (in this case, \(a\)), you subtract the bottom exponent from the top. So, \(a^{(-5)-(-8)}\).

    • one year ago
  18. geoffb
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    As for your numeric constants, you just divide them (\(12 \div 2\))

    • one year ago
  19. skylar87
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    ok so that will be -13

    • one year ago
  20. skylar87
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    5-8

    • one year ago
  21. geoffb
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    No, it's (-5) - (-8).

    • one year ago
  22. skylar87
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    12/2 is 6 -5-(-8)=3

    • one year ago
  23. geoffb
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    A double-negative is a positive (in math).

    • one year ago
  24. geoffb
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    Good!

    • one year ago
  25. geoffb
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    So what's your final answer?

    • one year ago
  26. skylar87
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    6a\[6a ^3\]

    • one year ago
  27. geoffb
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    Good!

    • one year ago
  28. skylar87
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    do I do the samething if my problem has 12 x top and 8y bottom

    • one year ago
  29. geoffb
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    Do you mean like: \(\Large{\frac{12x}{8y}}\) ? No, those are different variables, so you cannot divide one by the other.

    • one year ago
  30. geoffb
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    You can simplify the numbers \(\Large{\frac{12}{8} = \frac{3}{2}}\), but that's all.

    • one year ago
  31. skylar87
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    yes with -6 at the top and -10 at the bottom

    • one year ago
  32. geoffb
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    Ahh, so: \[\frac{12x^{-6}}{8y^{-10}}\] Nope, all you can simplify in this case is 12/8.

    • one year ago
  33. skylar87
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    3x,2y

    • one year ago
  34. geoffb
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    Yes, with the same exponents.

    • one year ago
  35. skylar87
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    so there isn't any steps to break it down because my teacher keep saying show your work

    • one year ago
  36. geoffb
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    If they're different variables, you can't simplify them further.

    • one year ago
  37. geoffb
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    The only "work" you could show is dividing both the top and bottom by 4, to simplify your numeric fraction.

    • one year ago
  38. geoffb
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    \[\Large\frac{12x^{-6}}{8y^{-10}} \small\frac{\div 4}{\div 4}\]

    • one year ago
  39. skylar87
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    ok

    • one year ago
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