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 2 years ago
A binary gap within a positive integer N is any maximal sequence of consecutive zeros that is surrounded by ones at both ends in the binary representation of N.
E.g.:
The number 20 has binary representation 10100 and contains one binary gap of length 1. The number 15 has binary representation 1111 and has no binary gaps.
Write a function: class Solution { public int binary_gap(int N); } that, given a positive integer N, returns the length of its longest binary gap. The function should return 0 if N doesn't contain a binary gap.
 2 years ago
A binary gap within a positive integer N is any maximal sequence of consecutive zeros that is surrounded by ones at both ends in the binary representation of N. E.g.: The number 20 has binary representation 10100 and contains one binary gap of length 1. The number 15 has binary representation 1111 and has no binary gaps. Write a function: class Solution { public int binary_gap(int N); } that, given a positive integer N, returns the length of its longest binary gap. The function should return 0 if N doesn't contain a binary gap.

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Luckycutie1
 2 years ago
Best ResponseYou've already chosen the best response.0this seems pretty hard of a problem

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.0just thinking aloud, I would approach it along the lines of: maxGap = 0 inGap = false while N > 0 if N % 2 == 1 if inGap AND gapLength > maxGap maxGap = gapLength inGap = true gapLength = 0 else: gapLength++ N = N >> 1 return maxGap

luan.cestari
 2 years ago
Best ResponseYou've already chosen the best response.1I made this program in python (just create a file with ".py" in the end put the code in it and use "python nameOfFile.py number", where 'number' can be any integer): """ Get the Max Gap """ import sys import re if __name__ == '__main__': number = int(sys.argv[1]) binNumber = bin(number) strBinNumber = binNumber.__str__() strBinNumber = re.split("0b", strBinNumber)[1] maxGap = 0 counter = 0 firstFound = False for c in list(strBinNumber): if c == '1': firstFound = True if maxGap < counter: maxGap = counter counter = 0 else: if firstFound: counter+=1 print(strBinNumber) print(maxGap)

g152xx
 2 years ago
Best ResponseYou've already chosen the best response.0Thank you very much all of you, I can't give 2 medals but @asnasser I'll prepare one for you on the next one. Thanks much.

atifmehar
 one year ago
Best ResponseYou've already chosen the best response.0I made this program in Java public int maxBinaryGap(int number) { int maxGap = 0; boolean inGap = false; int gapLength = 0; while (number > 0) { if (number % 2 == 1) { if (inGap && gapLength > maxGap) { maxGap = gapLength; } inGap = true; gapLength = 0; } else { gapLength++; } number = number >> 1; } return maxGap; }
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