JamenS
simplify
2log2(8x)



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geoffb
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Is that base2?
\[2 \log_{2}8x \]

JamenS
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yea

JamenS
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2log28x?

geoffb
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Okay. It's already fairly simplified, although you could get rid of the base2.
\[2 \log_{2}8x = \frac{2\log 8x}{\log 2}\]

JamenS
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16x?

JamenS
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8x?

JamenS
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8?

JamenS
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log2(8x)?

geoffb
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Ummm... no. I'm not sure if you're trying to solve it or if you're suggesting those should go after the log.

JamenS
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idk its a multiple choice question ?

geoffb
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Okay. Well, your answer will still have a log involved.