Tickets for a school play cost $5 if you buy them early, and $7 if you buy them the day of the show. If 200 tickets are sold, and the total amount of money from ticket sales was $1340, how many tickets were purchased early?
A. 170 tickets
B. 30 tickets
C. 100 tickets
D. 124 tickets
Let early tickets be \(x\). Since there are 200 total, late tickets must be \(200 - x\).
You also know that the sum of all tickets is $1340. So:
\[5x + 7(200-x) = 1340\]
Does that make sense to you?
Very good!
So once you solve for x, a very important step is to go back and look at what you chose x to represent. In this case, we chose for it to represent tickets purchased early. If we had let it represent tickets purchased late, you would end up with x = 170, but the answer *wouldn't* be A, because it is looking for tickets purchased early, not late.
Yes, and you can test it if you want (I would if you were doing a test.
30 early tickets x $5 = $150
170 late tickets x $7 = $1190
Total ticket revenue = $1340