anonymous
  • anonymous
Tickets for a school play cost $5 if you buy them early, and $7 if you buy them the day of the show. If 200 tickets are sold, and the total amount of money from ticket sales was $1340, how many tickets were purchased early? A. 170 tickets B. 30 tickets C. 100 tickets D. 124 tickets
Mathematics
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
C
anonymous
  • anonymous
@dietrich_harmon how? ;o
anonymous
  • anonymous
No kidding.

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More answers

anonymous
  • anonymous
Let early tickets be \(x\). Since there are 200 total, late tickets must be \(200 - x\). You also know that the sum of all tickets is $1340. So: \[5x + 7(200-x) = 1340\] Does that make sense to you?
anonymous
  • anonymous
@geoffb So it really is C?
anonymous
  • anonymous
Definitely not.
anonymous
  • anonymous
I thought so @geoffb. I thought it was A.
anonymous
  • anonymous
Careful...
anonymous
  • anonymous
Did you work out the formula above? Does it make sense how I got it and what it means?
anonymous
  • anonymous
So Id end up with 4x+1400=1340?
anonymous
  • anonymous
No, not 4x.
anonymous
  • anonymous
\[5x + 1400 - 7x = 1340\]
anonymous
  • anonymous
-2x+1400=1340
anonymous
  • anonymous
Yes, good.
anonymous
  • anonymous
x=30
anonymous
  • anonymous
Very good! So once you solve for x, a very important step is to go back and look at what you chose x to represent. In this case, we chose for it to represent tickets purchased early. If we had let it represent tickets purchased late, you would end up with x = 170, but the answer *wouldn't* be A, because it is looking for tickets purchased early, not late.
anonymous
  • anonymous
Does that make sense?
anonymous
  • anonymous
OH so its B
anonymous
  • anonymous
Yes, and you can test it if you want (I would if you were doing a test. 30 early tickets x $5 = $150 170 late tickets x $7 = $1190 Total ticket revenue = $1340
anonymous
  • anonymous
thanks @geoffb
anonymous
  • anonymous
You're welcome! :)

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