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IloveCharlie

  • 3 years ago

I need to refresh my memory :/ How would I graph y=(x+3)^2+1?

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  1. Jonask
    • 3 years ago
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    this is turning point form so the vertex is given

  2. hba
    • 3 years ago
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    First of all you need to simplify the equation :)

  3. hba
    • 3 years ago
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    Then you start assigning values for x and get y or assign for y and get x

  4. hba
    • 3 years ago
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    And then just plot them up on a graph sheet :)

  5. Jonask
    • 3 years ago
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    TP(-3,1) and the graphs intecepts can be seen when x=0 and when y=0

  6. IloveCharlie
    • 3 years ago
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    Wait, but what happened to the 2?

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