Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

UnkleRhaukusBest ResponseYou've already chosen the best response.1
\[\begin{align*}\frac1{p^2(p^24)}&=\frac1{p^2(p+2)(p2)}\\ \\&=\frac Ap+\frac B{p^2}+\frac C{p+2}+\frac D{p2}\\ \\\end{align*}\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
\[1=Ap(p+2)(p2)+B(p+2)(p2)+Cp^2(p2)+Dp^2(p+2)\]
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
Put Values for p and Find A , B , C D
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
1st put P = 2 and Find D
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
\[1=Ap(p+2)(p2)+B(p+2)(p2)+Cp^2(p2)+Dp^2(p+2)\] \[\text{for }p=0\\\qquad1=4B\]\[\qquad B=\frac{1}4\] \[\text{for }p=2\]\[\qquad1=16D\]\[\qquad D=\frac 1{16}\] \[\text{for }p=2\]\[\qquad1=16C\]\[\qquad C=\frac {1}{16}\] \[\text{for }p=1\]\[\qquad1=3A+3BC+3D\] \[\qquad1=3A\frac34+\frac 1{16}+\frac3{16}\]\[\qquad1=3A\frac34+\frac 4{16}\]\[\qquad\frac32=3A\]\[\qquad A=\frac{1}{2}\] \[\frac1{p^2(p^24)}=\frac 1{2p}\frac 1{4p^2}\frac 1{16(p+2)}+\frac 1{16(p2)}\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
i think \(A\) is ment to be zero , , can you see my mistake ?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
found it / (them)\[\begin{align*}\text{for }p=1&&1&=3A3BC+3D\\ &&1&=3A+\frac34+\frac 1{16}+\frac3{16}\\ &&1&=3A+1\\ \\ &&A&=0\\ \end{align*}\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
\[F(p)=\frac1{p^2(p^24)}=\frac 1{4p^2}\frac 1{16(p+2)}+\frac 1{16(p2)}\]
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.