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"the position of an object is described by the parametric equations x=ln t and y=5t^2. What is the accerleration of the object in m/sec^2 when t=2?"
 one year ago
 one year ago
"the position of an object is described by the parametric equations x=ln t and y=5t^2. What is the accerleration of the object in m/sec^2 when t=2?"
 one year ago
 one year ago

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inkyvoydBest ResponseYou've already chosen the best response.0
Now, what I did was calculuate d^2y/dt^2 and d^2x/dt^2. then I calculated \(\sqrt{a_x^2+a_y^2}\), for t=2...
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.0
But, my sister tells me I'm supposed to find d^2y/dx^2... what am I supposed to do?
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.0
http://chat.stackexchange.com/transcript/message/6955366#6955366
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.0
Question answered by people at math.stackexchange :) http://math.stackexchange.com/questions/241312/accelerationofaparticledescribedbyparametricequations
 one year ago

phiBest ResponseYou've already chosen the best response.0
accerleration of the object is the change in velocity of the object with time velocity is the change in position of the object with time The position of the object is the vector (x y) its velocity is the vector (dx/dt dy/dt) its acceleration is the vector (d^2 x/dt^2 d^2 y/dt^2) You found the magnitude of the acceleration, which may or may not be what the question is asking for.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.0
@phi , the problem is that the units they want are in m/sec^2  so direction wouldn't really do anything in here :S
 one year ago
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