## inkyvoyd Group Title "the position of an object is described by the parametric equations x=ln t and y=5t^2. What is the accerleration of the object in m/sec^2 when t=2?" one year ago one year ago

1. inkyvoyd Group Title

Now, what I did was calculuate d^2y/dt^2 and d^2x/dt^2. then I calculated $$\sqrt{a_x^2+a_y^2}$$, for t=2...

2. inkyvoyd Group Title

But, my sister tells me I'm supposed to find d^2y/dx^2... what am I supposed to do?

3. inkyvoyd Group Title

@amistre64

4. inkyvoyd Group Title
5. inkyvoyd Group Title

Question answered by people at math.stackexchange :) http://math.stackexchange.com/questions/241312/acceleration-of-a-particle-described-by-parametric-equations

6. phi Group Title

accerleration of the object is the change in velocity of the object with time velocity is the change in position of the object with time The position of the object is the vector (x y) its velocity is the vector (dx/dt dy/dt) its acceleration is the vector (d^2 x/dt^2 d^2 y/dt^2) You found the magnitude of the acceleration, which may or may not be what the question is asking for.

7. inkyvoyd Group Title

@phi , the problem is that the units they want are in m/sec^2 - so direction wouldn't really do anything in here :S