"the position of an object is described by the parametric equations x=ln t and y=5t^2. What is the accerleration of the object in m/sec^2 when t=2?"

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"the position of an object is described by the parametric equations x=ln t and y=5t^2. What is the accerleration of the object in m/sec^2 when t=2?"

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Now, what I did was calculuate d^2y/dt^2 and d^2x/dt^2. then I calculated \(\sqrt{a_x^2+a_y^2}\), for t=2...
But, my sister tells me I'm supposed to find d^2y/dx^2... what am I supposed to do?

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http://chat.stackexchange.com/transcript/message/6955366#6955366
Question answered by people at math.stackexchange :) http://math.stackexchange.com/questions/241312/acceleration-of-a-particle-described-by-parametric-equations
  • phi
accerleration of the object is the change in velocity of the object with time velocity is the change in position of the object with time The position of the object is the vector (x y) its velocity is the vector (dx/dt dy/dt) its acceleration is the vector (d^2 x/dt^2 d^2 y/dt^2) You found the magnitude of the acceleration, which may or may not be what the question is asking for.
@phi , the problem is that the units they want are in m/sec^2 - so direction wouldn't really do anything in here :S

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