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eroshea Group Title

An isosceles triangle ABC, in which AB=BC=6 root 2 and AC=12 is folded along the altitude BD so that planes ABD and BDC form a right dihedral angle. Find the angle between side AB and its new position.

  • 2 years ago
  • 2 years ago

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  1. experimentX Group Title
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    could you draw a bit of figure?

    • 2 years ago
  2. eroshea Group Title
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    i can't .. that is my problem, too..

    • 2 years ago
  3. experimentX Group Title
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    |dw:1353425869624:dw|

    • 2 years ago
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    |dw:1353426012864:dw|

    • 2 years ago
  5. eroshea Group Title
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    so what i'm going to find is the theta??

    • 2 years ago
  6. eroshea Group Title
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    Find the angle between side AB and its new position. what does this mean?

    • 2 years ago
  7. experimentX Group Title
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    i guess that's the angle you are going to find ... can you find it?

    • 2 years ago
  8. eroshea Group Title
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    i need further solution/explanation

    • 2 years ago
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    |dw:1353426445410:dw|

    • 2 years ago
  10. eroshea Group Title
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    that is 90 degrees

    • 2 years ago
  11. eroshea Group Title
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    i used cosine law

    • 2 years ago
  12. experimentX Group Title
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    \( \theta \) will be half of \( \alpha \)

    • 2 years ago
  13. eroshea Group Title
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    45 ?

    • 2 years ago
  14. eroshea Group Title
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    the book's answer is 60 degrees.. but i find it 45 degrees.. how did it ended up with 60?

    • 2 years ago
  15. experimentX Group Title
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    yep .. should be around like that if you did it properly!!

    • 2 years ago
  16. eroshea Group Title
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    aawww. can you explain it ?

    • 2 years ago
  17. experimentX Group Title
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    looks like you did it right http://www.wolframalpha.com/input/?i=12^2+%3D+2%286+sqrt%282%29%29^2+-+2+*+%286+sqrt%282%29%29^2+cos%28x%29

    • 2 years ago
  18. eroshea Group Title
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    b^2 = a^2 + c^2 - 2ac cos theta that is cosine law right? and the answer is 90 degrees

    • 2 years ago
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