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anonymous
 3 years ago
Evaluate the integral ∬sin(x^2+y^2 )dA where R is the region that lies above the xaxis within the circle x^2 +y^2 =16 by changing into polar coordinates.
anonymous
 3 years ago
Evaluate the integral ∬sin(x^2+y^2 )dA where R is the region that lies above the xaxis within the circle x^2 +y^2 =16 by changing into polar coordinates.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0as for radius is from 4 to 4. for angle is from 0 to 180 ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0differentiate by r dr dθ ?

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1use radiant (0 to pi)!! and dA = r dr d(theta)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok. let me work out....

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1\[ \int_0^4 \int_0^\pi \sin ( r^2 \cos^2 \theta + r^2 \sin^2 \theta) \; r \; dr\; d\theta \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0could u pls explain to me why e radius is from 0 to 4 nt 4 to 4? and hw to get e function?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok i understood. hw abt e integration part?

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1\[ \int_0^4 \int_0^\pi \sin ( r^2) \; r \; d\theta\; dr\ \\ \int_0^4 \sin ( r^2) \; r \; \left [ \theta \right ]_0^\pi dr\\ \] just use subs r^2 = u

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok...thanks. let me work out

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is the ans \[ \pi \cos8

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1http://www.wolframalpha.com/input/?i=Integrate [Integrate[Sin[r^2]r%2C+{theta%2C+0%2C+pi}]%2C+{r%2C0%2C+4}] check it out again

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1Integrate[Integrate[Sin[r^2]r, {theta, 0, pi}], {r,0, 4}]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i need guidance pls...

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1353425265831:dw

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1do your integration and arrive at \[ \pi [ \cos 0  \cos 16] \over 2\\ = {\pi(1  \cos 16) \over 2 }\]just use half angle formula

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0do i need to use mehod by substitution for r^2
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