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mathstina
Group Title
Evaluate the integral ∬sin(x^2+y^2 )dA where R is the region that lies above the xaxis within the circle x^2 +y^2 =16 by changing into polar coordinates.
 one year ago
 one year ago
mathstina Group Title
Evaluate the integral ∬sin(x^2+y^2 )dA where R is the region that lies above the xaxis within the circle x^2 +y^2 =16 by changing into polar coordinates.
 one year ago
 one year ago

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mathstina Group TitleBest ResponseYou've already chosen the best response.0
as for radius is from 4 to 4. for angle is from 0 to 180 ?
 one year ago

mathstina Group TitleBest ResponseYou've already chosen the best response.0
differentiate by r dr dθ ?
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
use radiant (0 to pi)!! and dA = r dr d(theta)
 one year ago

mathstina Group TitleBest ResponseYou've already chosen the best response.0
ok. let me work out....
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
\[ \int_0^4 \int_0^\pi \sin ( r^2 \cos^2 \theta + r^2 \sin^2 \theta) \; r \; dr\; d\theta \]
 one year ago

mathstina Group TitleBest ResponseYou've already chosen the best response.0
could u pls explain to me why e radius is from 0 to 4 nt 4 to 4? and hw to get e function?
 one year ago

mathstina Group TitleBest ResponseYou've already chosen the best response.0
ok i understood. hw abt e integration part?
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
\[ \int_0^4 \int_0^\pi \sin ( r^2) \; r \; d\theta\; dr\ \\ \int_0^4 \sin ( r^2) \; r \; \left [ \theta \right ]_0^\pi dr\\ \] just use subs r^2 = u
 one year ago

mathstina Group TitleBest ResponseYou've already chosen the best response.0
ok...thanks. let me work out
 one year ago

mathstina Group TitleBest ResponseYou've already chosen the best response.0
is the ans \[ \pi \cos8
 one year ago

mathstina Group TitleBest ResponseYou've already chosen the best response.0
\[\pi \cos 8\]
 one year ago

mathstina Group TitleBest ResponseYou've already chosen the best response.0
am i right??
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
http://www.wolframalpha.com/input/?i=Integrate[Integrate[Sin[r^2]r%2C+{theta%2C+0%2C+pi}]%2C+{r%2C0%2C+4}] check it out again
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
Integrate[Integrate[Sin[r^2]r, {theta, 0, pi}], {r,0, 4}]
 one year ago

mathstina Group TitleBest ResponseYou've already chosen the best response.0
i need guidance pls...
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
dw:1353425265831:dw
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
do your integration and arrive at \[ \pi [ \cos 0  \cos 16] \over 2\\ = {\pi(1  \cos 16) \over 2 }\]just use half angle formula
 one year ago

mathstina Group TitleBest ResponseYou've already chosen the best response.0
do i need to use mehod by substitution for r^2
 one year ago
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