A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Evaluate the integral ∬sin(x^2+y^2 )dA where R is the region that lies above the xaxis within the circle x^2 +y^2 =16 by changing into polar coordinates.
anonymous
 4 years ago
Evaluate the integral ∬sin(x^2+y^2 )dA where R is the region that lies above the xaxis within the circle x^2 +y^2 =16 by changing into polar coordinates.

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0as for radius is from 4 to 4. for angle is from 0 to 180 ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0differentiate by r dr dθ ?

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1use radiant (0 to pi)!! and dA = r dr d(theta)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok. let me work out....

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1\[ \int_0^4 \int_0^\pi \sin ( r^2 \cos^2 \theta + r^2 \sin^2 \theta) \; r \; dr\; d\theta \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0could u pls explain to me why e radius is from 0 to 4 nt 4 to 4? and hw to get e function?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok i understood. hw abt e integration part?

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1\[ \int_0^4 \int_0^\pi \sin ( r^2) \; r \; d\theta\; dr\ \\ \int_0^4 \sin ( r^2) \; r \; \left [ \theta \right ]_0^\pi dr\\ \] just use subs r^2 = u

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok...thanks. let me work out

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is the ans \[ \pi \cos8

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1http://www.wolframalpha.com/input/?i=Integrate [Integrate[Sin[r^2]r%2C+{theta%2C+0%2C+pi}]%2C+{r%2C0%2C+4}] check it out again

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1Integrate[Integrate[Sin[r^2]r, {theta, 0, pi}], {r,0, 4}]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i need guidance pls...

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1353425265831:dw

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1do your integration and arrive at \[ \pi [ \cos 0  \cos 16] \over 2\\ = {\pi(1  \cos 16) \over 2 }\]just use half angle formula

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0do i need to use mehod by substitution for r^2
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.