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anonymous
 3 years ago
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anonymous
 3 years ago
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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0First question, why is \(U_i=mgh_f\) instead of \(U_i = mgh_i\)?

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.0that is the total energy of the system!! the energy of the system is constant if there were no other forces acting. i.e. Kinetic Energy + Potential Energy = constant = total energy now given that the pendulum starts from rest at height h_i, K.E. = 0, total energy = P.E

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0But with the initial height hi, isn't the PE = \(mgh_i\)? Why is it \(mgh_f\)?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1353427300243:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Initial PE = mg(llcosθi) = mgl (1cosθi) Final PE = mg(llcosθf)= mgl(1cosθf) PE loss = change in PE = mgl[(1cosθf)  (1cosθi)] = mgl(cosθi  cosθf) ??

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1353430286611:dw

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.0since l is defined as the distanced from pivoted point to the center of mass ... the energy of the system is \( mgl (1  \cos \theta) \) ... this is the total energy of the system ... probably experiment expects you to observe until the blob halt's to move.
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