Here's the question you clicked on:
vivalakoda
I need help real quick with this radical question?
\[\frac{ 2 }{ 6-√3 } \]
rationalize the denominator?
How? Do you just multiply the top and bottom by √3?
\[\frac{2}{6-\sqrt{3}}*\frac{(6+\sqrt{3})}{(6+\sqrt{3})}=\frac{12+2\sqrt{3}}{36-3}=\frac{12+2\sqrt{3}}{33}\]
No...you are suppose to multiply the numerator and denominator by the reciprocal of 6-\[\sqrt{3}\} Which would be 6+
Ohhhh. Okay that makes a lot more sense. With online school I can't really ask for help to understand things. Hard to just read a text and go off of it. Thanks so much, guys!