## anonymous 4 years ago I need help real quick with this radical question?

1. anonymous

$\frac{ 2 }{ 6-√3 }$

2. anonymous

rationalize the denominator?

3. anonymous

How? Do you just multiply the top and bottom by √3?

4. anonymous

$\frac{2}{6-\sqrt{3}}*\frac{(6+\sqrt{3})}{(6+\sqrt{3})}=\frac{12+2\sqrt{3}}{36-3}=\frac{12+2\sqrt{3}}{33}$

5. dinmosiaren

No...you are suppose to multiply the numerator and denominator by the reciprocal of 6-$\sqrt{3}\} Which would be 6+ 6. dinmosiaren \[\sqrt{3}$

7. anonymous

Ohhhh. Okay that makes a lot more sense. With online school I can't really ask for help to understand things. Hard to just read a text and go off of it. Thanks so much, guys!