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vivalakoda Group Title

I need help real quick with this radical question?

  • 2 years ago
  • 2 years ago

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  1. vivalakoda Group Title
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    \[\frac{ 2 }{ 6-√3 } \]

    • 2 years ago
  2. eseidl Group Title
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    rationalize the denominator?

    • 2 years ago
  3. vivalakoda Group Title
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    How? Do you just multiply the top and bottom by √3?

    • 2 years ago
  4. eseidl Group Title
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    \[\frac{2}{6-\sqrt{3}}*\frac{(6+\sqrt{3})}{(6+\sqrt{3})}=\frac{12+2\sqrt{3}}{36-3}=\frac{12+2\sqrt{3}}{33}\]

    • 2 years ago
  5. dinmosiaren Group Title
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    No...you are suppose to multiply the numerator and denominator by the reciprocal of 6-\[\sqrt{3}\} Which would be 6+

    • 2 years ago
  6. dinmosiaren Group Title
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    \[\sqrt{3}\]

    • 2 years ago
  7. vivalakoda Group Title
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    Ohhhh. Okay that makes a lot more sense. With online school I can't really ask for help to understand things. Hard to just read a text and go off of it. Thanks so much, guys!

    • 2 years ago
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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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