## vivalakoda Group Title I need help real quick with this radical question? one year ago one year ago

1. vivalakoda Group Title

$\frac{ 2 }{ 6-√3 }$

2. eseidl Group Title

rationalize the denominator?

3. vivalakoda Group Title

How? Do you just multiply the top and bottom by √3?

4. eseidl Group Title

$\frac{2}{6-\sqrt{3}}*\frac{(6+\sqrt{3})}{(6+\sqrt{3})}=\frac{12+2\sqrt{3}}{36-3}=\frac{12+2\sqrt{3}}{33}$

5. dinmosiaren Group Title

No...you are suppose to multiply the numerator and denominator by the reciprocal of 6-$\sqrt{3}\} Which would be 6+ 6. dinmosiaren Group Title \[\sqrt{3}$

7. vivalakoda Group Title

Ohhhh. Okay that makes a lot more sense. With online school I can't really ask for help to understand things. Hard to just read a text and go off of it. Thanks so much, guys!