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vivalakoda

  • 3 years ago

I need help real quick with this radical question?

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  1. vivalakoda
    • 3 years ago
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    \[\frac{ 2 }{ 6-√3 } \]

  2. eseidl
    • 3 years ago
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    rationalize the denominator?

  3. vivalakoda
    • 3 years ago
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    How? Do you just multiply the top and bottom by √3?

  4. eseidl
    • 3 years ago
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    \[\frac{2}{6-\sqrt{3}}*\frac{(6+\sqrt{3})}{(6+\sqrt{3})}=\frac{12+2\sqrt{3}}{36-3}=\frac{12+2\sqrt{3}}{33}\]

  5. dinmosiaren
    • 3 years ago
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    No...you are suppose to multiply the numerator and denominator by the reciprocal of 6-\[\sqrt{3}\} Which would be 6+

  6. dinmosiaren
    • 3 years ago
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    \[\sqrt{3}\]

  7. vivalakoda
    • 3 years ago
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    Ohhhh. Okay that makes a lot more sense. With online school I can't really ask for help to understand things. Hard to just read a text and go off of it. Thanks so much, guys!

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