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snaef999
A particle starts at the origin and initial verlocity is i - j + 3k. Its acceleration is a(t) = 6t i + 12t^2 j + 6t k. Find its position function. I need help confirming my answer. Is the correct way to do this to integrate a(t) to get velocity and then integrate velocity to get position?
yeah. You are also given it's initial velocity
When finding velocity I need to use the initial velocity as the C right?
Yes, the constant of integration after the first integration is your initial velocity
My final answer is (t^3 + t)i + (t^4 -t)j + (2/3 t^3 + 3t)k + c (c = 0 because we started at the origin)
hang on...i'll check and see what I get
I get s(t)=(t^3+t)i+(t^4-t)j+(t^3-3t)k
Ah. I see what I did wrong. Thank you for your help! I looked at the wrong numbers for k when I was dong position integral. It works for me now.